It is currently 22 Nov 2017, 19:22

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# 4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the

Author Message
CEO
Joined: 15 Aug 2003
Posts: 3452

Kudos [?]: 926 [0], given: 781

4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the [#permalink]

### Show Tags

10 Oct 2003, 21:35
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the probability of

1. Picking one of each color

(4C1* 5C1*6C1 ) / (15C3) correct ?

2. Picking 3 of the same color.

( 4C3 + 5C3 + 6C3 ) / 15C3 correct ?

3. Picking 2 of the same color.

simpler way to do this??

thanks
praetorian

Kudos [?]: 926 [0], given: 781

Intern
Joined: 29 Aug 2003
Posts: 47

Kudos [?]: 2 [0], given: 0

Location: Detroit, MI
Re: PS : Probability ... Colors [#permalink]

### Show Tags

12 Oct 2003, 19:42
praetorian123 wrote:
4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the probability of

1. Picking one of each color

(4C1* 5C1*6C1 ) / (15C3) correct ?

2. Picking 3 of the same color.

( 4C3 + 5C3 + 6C3 ) / 15C3 correct ?

3. Picking 2 of the same color.

simpler way to do this??

thanks
praetorian

I would approach #3 like this.

(4C2*11C1 + 5C2*10C1 + 6C2*9C1)/15C3

Is this right?

Amar.

Kudos [?]: 2 [0], given: 0

SVP
Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 308 [0], given: 0

Re: PS : Probability ... Colors [#permalink]

### Show Tags

13 Oct 2003, 01:10
praetorian123 wrote:
4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the probability of

1. Picking one of each color

(4C1* 5C1*6C1 ) / (15C3) correct ?

2. Picking 3 of the same color.

( 4C3 + 5C3 + 6C3 ) / 15C3 correct ?

3. Picking 2 of the same color.

simpler way to do this??

thanks
praetorian

(1) agree
(2) agree
(3) if exactly two of the same color plus one of other color, then
(4C2*11 + 5C2*10 + 6C2*9) / 15C3

2 of red+1 of NOT red (11C1=11) and so on

Kudos [?]: 308 [0], given: 0

Re: PS : Probability ... Colors   [#permalink] 13 Oct 2003, 01:10
Display posts from previous: Sort by