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Updated on: 22 Aug 2012, 16:51
Originally posted by feellikequitting on 22 Aug 2012, 11:17.
Last edited by feellikequitting on 22 Aug 2012, 16:51, edited 1 time in total.
Last edited by feellikequitting on 22 Aug 2012, 16:51, edited 1 time in total.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
81% (00:54) correct
19%
(01:20)
wrong
based on 225
sessions
History
Date
Time
Result
Not Attempted Yet
22 Aug 2012, 11:58
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laythesmack23
You have given the OA as B, but you can see by plugging x = -1/3 into the equation that B is not the right answer.
We can solve - expand the right side, multiply by x on both sides and then subtract away the 3x^2 terms:
(4/X) + 3x = 3(x-12)
(4/x) + 3x = 3x - 36
4 + 3x^2 = 3x^2 - 36x
4 = -36x
-1/9 = x
and to confirm, you can plug that answer back into the original equation to see that it makes the left and right sides equal.
22 Aug 2012, 16:51
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Dude, you're awesome! Yeah, it was my mistake, correct answer is C! I see what you did, you did it much easier than the mgmat website.
When simplifying the equation like 4/X + 3X= 3X-36, to remove the denominator, we multiply with 3X,by both sides, is this correct? And this gives us 4+3x^2=3x^2-36 (are you multiplying by X on the left side to both sides? to square both 3X's?, I'm assuming this isolates the problem to 4=-36? then you divide by 4.
I don't follow why this becomes
When simplifying the equation like 4/X + 3X= 3X-36, to remove the denominator, we multiply with 3X,by both sides, is this correct? And this gives us 4+3x^2=3x^2-36 (are you multiplying by X on the left side to both sides? to square both 3X's?, I'm assuming this isolates the problem to 4=-36? then you divide by 4.
I don't follow why this becomes
