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24 Jan 2020, 02:56
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24 Jan 2020, 03:12
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\(\frac{6^4 - 6^3}{5} =\)
Taking \(6^3\) common, we get
\(6^3(\frac{6 - 1}{5})\)
\(6^3(\frac{5}{5})\)
\(6^3\) ... 'B' is the winner
Taking \(6^3\) common, we get
\(6^3(\frac{6 - 1}{5})\)
\(6^3(\frac{5}{5})\)
\(6^3\) ... 'B' is the winner
Bunuel
\(\frac{6^4 - 6^3}{5} =\)
A. 1/5
B. 6^3
C. 6/5
D. 6^4
E. 6^3/5
A. 1/5
B. 6^3
C. 6/5
D. 6^4
E. 6^3/5
24 Jan 2020, 03:39
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\(\frac{6^3(6-1)}{5}\) => \(\frac{6^3(5)}{5}\)
= \(6^3\)
Option B
= \(6^3\)
Option B
