rsrighosh
Hi
KarishmaB &
12921Could you please help me to identify the mistake.
I am unable to understand what mistake I am doing in my approach.
Total unit of work = 30 units
A works 2 units/day and B works 3 units/day
Together A and B work 5 units/ day
Let total time taken is t
(t-3)5 + 3*3 = 30
Hence t = 36/5
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I though understand logically that 30 units of work if together A&B work, then both of them are supposed to finish it in 30/5 = 6 days.
As A & B work for 3 days so they finish 15 units. And the rest 15 units of work is finished by B in 15/3 = 5 days
So total is 8 days
But why the algebraic approach is giving wrong answer?The answer here is 36/5 days, not 8 days.
The algebraic approach used by you is correct above.
Assuming 30 units of work, A does 2 units and B does 3 units every day.
Last 3 days, only B works so he does 9 units in that time. So we are left with 21 units if work which A and B do together first.
21 units of work will take 21/5 days (since A and B are working together)
Total time taken will be 36/5 days.