Option A:Size of box - L =11, W = 10 & H =7. To be filled with wooden cubes of side 3 (l = w = h 3).
: Can start with putting cubes one over another - max number of cubes which can be put together in this pattern =
2 (total h = 3 + 3 = 6, which is constrained by the height H, of box = 7)
: Now, this set of 2 cubes (one over other) can be placed together, max number of such sets which can be put together along the length =
3 (total l of cubes = =3*3 = 9, which is constrained by the length L, of box = 11)
: Similarly, these sets can be placed along the width, max number of such sets which can be put together along the width =
3 (total w of cubes = =3*3 = 9, which is constrained by the width W, of box = 10)
Total number wooden cubes = 2*3*3 = 18
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