Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1012:01 AM PST
-11:59 PM PST
On Tuesday the 10th, GMAT Club Tests will be Absolutely Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PST- Dec 10
10:00 AM PST
-11:00 AM PST
Is it possible to achieve a stellar GMAT score in just 30 days while balancing a full-time job? Join us for an exclusive live interview with Keshav, who scored an impressive 705 (Q88, V83, D84) on the GMAT in just 30 days 
Dec 1310:00 AM EST
-12:00 PM EST
Have you ever wondered how to score a PERFECT 805 on the GMAT? Meet Julia, a banking professional who used the Target Test Prep course to achieve this incredible feat. Julia's story is nothing short of an inspiration.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.
Dec 1411:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.- Dec 15
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. - Dec 16
08:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
17 Apr 2010, 01:52
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
68% (02:05) correct
32%
(02:07)
wrong
based on 200
sessions
History
Date
Time
Result
Not Attempted Yet
A certain carton holds fewer than 50 books. What is the number of books in the carton?
(1) The books in the carton can be divided into 3 stacks of X books each, with 2 books lefts over.
(2) The books in the carton can be divided into Y stacks of 7 books each , with 2 books left over.
(1) The books in the carton can be divided into 3 stacks of X books each, with 2 books lefts over.
(2) The books in the carton can be divided into Y stacks of 7 books each , with 2 books left over.
17 Apr 2010, 05:16
Kudos
Bookmarks
nilesh376
A certain carton holds fewer than 50 books. What is the number of books in the carton?
1. The books in the carton can be divided into 3 stacks of X books each, with 2 books lefts over.
2. The books in the carton can be divided into Y stacks of 7 books each , with 2 books left over.
Please provide ur answer with explanation??
1. The books in the carton can be divided into 3 stacks of X books each, with 2 books lefts over.
2. The books in the carton can be divided into Y stacks of 7 books each , with 2 books left over.
Please provide ur answer with explanation??
(1) Basically statement tells that the number of books divided by 3 gives remainder of 2 --> \(n=3x+2<50\) --> multiple values of \(n\) are possible. Not sufficient.
(2) Basically statement tells that the number of books divided by 7 gives remainder of 2 --> \(n=7y+2<50\) --> multiple values of \(n\) are possible. Not sufficient.
(1)+(2) \(n=21k+2<50\) --> \(k=1\), \(n=23<50\) or \(k=2\), \(n=44<50\). Not sufficient.
Answer: E.
General Discussion
17 Apr 2010, 02:21
Kudos
Bookmarks
IMO C.
Total books < 50.
1. The books in the carton can be divided into 3 stacks of X books each, with 2 books lefts over. [Insuff]
If the no. of books = 5 and per stack 1 book
If the no. of books = 8 and per stack 2 book, and so on.
2. The books in the carton can be divided into Y stacks of 7 books each , with 2 books left over.
Let Y = 2 the total books = 16
Let Y = 3 the total books = 23. [Insuff]
On combining 1) and 2):
3 stacks each with 7 books
So total books can be 23.
Total books < 50.
1. The books in the carton can be divided into 3 stacks of X books each, with 2 books lefts over. [Insuff]
If the no. of books = 5 and per stack 1 book
If the no. of books = 8 and per stack 2 book, and so on.
2. The books in the carton can be divided into Y stacks of 7 books each , with 2 books left over.
Let Y = 2 the total books = 16
Let Y = 3 the total books = 23. [Insuff]
On combining 1) and 2):
3 stacks each with 7 books
So total books can be 23.
