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A certain library assesses fines for overdue books as follow [#permalink]

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17 Apr 2010, 06:10

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A

B

C

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E

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42% (00:45) wrong based on 1158 sessions

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A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a book on the fourth day it is overdue?

A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60 B. $0.70 C. $0.80 D. $0.90 E. $1.00

Notice that, fines are already cumulative: "For each additional day that the book is overdue, the total fine is ..."

1st day fine - 0.1 2nd day fine - 0.1*2 = 0.2 (as doubling gives lower value) 3rd day fine - 0.2*2 = 0.4 (as doubling gives lower value) 4th day fine - 0.4 + 0.3 = 0.7 (as doubling gives higher value we add 0.3 this time)

a certain library assess fines for overdue books as follows, on the first day that book is overdue , the total fine is 0.10. for each additional day that is overdue , the total fine is either inc by .30 or doubled, whichever results in lesser amount. What is the total fine for a book on the fourth day it is over due? .60 .70 .80 .90 1.00. I am getting .90 answer. my Reasoning is as follows 1(day) .10 2(day) .20 ( 2(.10)= .20 or.30 ,lesser amount .20) 3(day) .30 (2(.20)= .40 or .30, lesser amt= .30) 4(day) .30 (2(.30) =.60 or .30, lesser amount = .30) total = .90. I dont know what am i missing?

a certain library assess fines for overdue books as follows, on the first day that book is overdue , the total fine is 0.10. for each additional day that is overdue , the total fine is either inc by .30 or doubled, whichever results in lesser amount. What is the total fine for a book on the fourth day it is over due? .60 .70 .80 .90 1.00. I am getting .90 answer. my Reasoning is as follows 1(day) .10 2(day) .20 ( 2(.10)= .20 or.30 ,lesser amount .20) 3(day) .30 (2(.20)= .40 or .30, lesser amt= .30) 4(day) .30 (2(.30) =.60 or .30, lesser amount = .30) total = .90. I dont know what am i missing?

First of all you made an error calculating 4th day: 4th day fine - 0.4+0.3=0.7 (as doubling gives higher value we add 0.3 this time)

Next you should't add up fines as they are already cumulative: "For each additional day that the book is overdue, the total fine is ..."
_________________

A certain library assesses fines for overdue book as follows. On the first day that a book is overdue, the total fine is $0.10, for each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount, what is the total fine for a book on the fourth day it is overdue.

$0.60 $0.70 $0.80 $0.90 $1.00

OA:B

i know, this seems simple, but couldnt crack it,,,,,,,,,,,,,i dont know what my brain is thinking,,,,may be a movie or a budlight,,,,,,,

Day 1 : 0.1 Day 2 : Min{0.1x2,0.1+0.3}=0.2 Day 3 : Min{0.2x2,0.2+0.3}=0.4 Day 4 : Min{0.4x2,0.4+0.3}=0.7

A certain library assesses fines for overdue books as follow [#permalink]

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03 Feb 2012, 08:32

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A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is increased by $0.30 or doubled, whichever results in a lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60 B. $0.70 C. $0.80 D. $0.90 E. $1.00

i approached it and got 1.00, but i cant understand why .70, which is B Someone care to show me how to approach this question thanks
_________________

A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is increased by $0.30 or doubled, whichever results in a lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60 B. $0.70 C. $0.80 D. $0.90 E. $1.00

i approached it and got 1.00, but i cant understand why .70, which is B Someone care to show me how to approach this question thanks

Notice that, fines are already cumulative: "For each additional day that the book is overdue, the total fine is ..."

1st day fine - 0.1 2nd day fine - 0.1*2=0.2 (as doubling gives lower value) 3rd day fine - 0.2*2=0.4 (as doubling gives lower value) 4th day fine - 0.4+0.3=0.7 (as doubling gives higher value we add 0.3 this time)

Re: A certain library assesses fines for overdue books as follow [#permalink]

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16 Jan 2013, 14:10

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the total fine is increased by $0.30 or doubled, whichever results in a lesser amount - Keep the bolded phrases in mind .. it is quite confusing though .. Day 1 - $.10 Day 2- $.10 *2 or $.10+$.30 (Whichever results in a lesser amount), hence its $.20 Day 3 - $.20*2 or $.20+$.30, $.40 as its lesser Day 4 - $.40*2 or $.40+$.30, $.70 as this is lesser

Re: A certain library assesses fines for overdue books as follow [#permalink]

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20 Apr 2013, 05:08

cyberjadugar wrote:

Hi,

I am little confused, since the question mentions that the total fine be increased by 0.3 or double, won't the question be solved in following way:

day 1 - 0.1 day 2 - 2*0.1 = 0.2 day 3 (total due = 0.3, day 1 + day 2) = 0.6 day 4 = 0.9

can anyone please point out the mistake in my understanding of the question?

Regards,

Total fine at the end of the 2nd day = 0.2. This means that the total fine, including the past fines, at the end of the second day is 0.2. Notice that 0.1 has already been accounted for.Thus, when you are calculating the total fine at the end of the third day, you refer to 0.2. Thus, total fine at the end of the third day is 0.2*2=0.4.
_________________

Re: Total fine of book on the 4th day of its overdue ? [#permalink]

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23 Apr 2013, 03:17

This one's tricky for sure. Easy to fall for D. Here's the solution Day 1 = 0.1$ Day 2 ( Double or increase by 0.3$, chose the minimum one) Option1: Double -> 0.1*2= 0.2$ Option2: Increase by 0.3$ -> 0.1+0.3 = 0.4$ Minimum one: 0.2$ Day 3 Option1: Double -> 0.2*2=0.4$ Option2: Increase by 0.3$ -> 0.2+0.3=0.5$ Minimum one: 0.4$ Day 4 Option1: Double -> 0.4*2=0.8$ Option2: Increase by 0.3$ -> 0.4+0.3=0.7$ Minimum one: 0.7$ hence the OA.
_________________

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