zaarathelab wrote:

A certain liquid leaks out of a container at the rate of k liters for every x hours. If the

liquid costs $6 per liter, what is the cost, in dollars, of the amount of the liquid that will

leak out in y hours?

A) \(\frac {ky}{6x}\)

B) \(\frac {6x}{ky}\)

c) \(\frac {6k}{xy}\)

d) \(\frac {6ky}{x}\)

e) \(\frac {6xy}{k}\)

With this problem solving question it would be easier to plug in numbers.

Let's say that:

K=5

X=1

6=6

Y=10

So the liquid leaks out at a rate of 5l per hour, every litre cost 6$ and every hour costs 30$.

If Y= 10 the cost of the liquid per hour (30$) multiplied by Y(10) equals 300.

Our target is 300.

Plug in the numbers in the answer choices and the answer that yelds 300 will be the right one.

A \(\frac {ky}{6x}\) = 5(10)/6= 8.333333

B \(\frac {6x}{ky}\) = 6/5(10)= 0.12

C \(\frac {6k}{xy}\) = 6(5)/10 = 3

D \(\frac {6ky}{x}\) = 6(5)(10)/1 = 300

CORRECT (we could stop at D but if you have time go ahead)

E \(\frac {6xy}{k}\) = 60/5 = 12