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# A certain liquid leaks out of a container at the rate of k liters for

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A certain liquid leaks out of a container at the rate of k liters for  [#permalink]

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14 Jan 2010, 07:01
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A certain liquid leaks out of a container at the rate of k liters for every x hours. If the liquid costs $6 per liter, what is the cost, in dollars, of the amount of the liquid that will leak out in y hours? A) $$\frac {ky}{6x}$$ B) $$\frac {6x}{ky}$$ C) $$\frac {6k}{xy}$$ D) $$\frac {6ky}{x}$$ E) $$\frac {6xy}{k}$$ ##### Most Helpful Community Reply Current Student Joined: 23 May 2013 Posts: 186 Location: United States Concentration: Technology, Healthcare GMAT 1: 760 Q49 V45 GPA: 3.5 A certain liquid leaks out of a container at the rate of k liters for [#permalink] ### Show Tags 31 Dec 2014, 07:48 5 1 For these questions, start with the only value that is NOT a ratio and start canceling units. In this case, that's 'y' hours. $$y \ hours * \frac{ k \ liters }{x hours} *\frac{6}{liter} = \frac{6yk}{x}.$$ Answer: D ##### General Discussion Manager Joined: 06 Jan 2010 Posts: 55 Re: A certain liquid leaks out of a container at the rate of k liters for [#permalink] ### Show Tags 14 Jan 2010, 07:27 1 lts lost per hour = k/x lts lost in y hours = k*y/x total cost = 6ky/x hence D Manager Joined: 17 Aug 2009 Posts: 169 Re: A certain liquid leaks out of a container at the rate of k liters for [#permalink] ### Show Tags 14 Jan 2010, 12:33 1 3 The way I see it If it loses k liters in x hours, then in 1 hour it loses k/x. Therefore, in y hours it would lose (k/x) * y Therefore total cost = 6ky/x D is the answer Intern Joined: 17 May 2014 Posts: 5 Location: United Kingdom Concentration: General Management, Finance GMAT 1: 470 Q28 V27 GPA: 3.4 WE: Accounting (Retail) Re: A certain liquid leaks out of a container at the rate of k liters for [#permalink] ### Show Tags 17 Dec 2014, 05:52 4 zaarathelab wrote: A certain liquid leaks out of a container at the rate of k liters for every x hours. If the liquid costs$6 per liter, what is the cost, in dollars, of the amount of the liquid that will
leak out in y hours?

A) $$\frac {ky}{6x}$$

B) $$\frac {6x}{ky}$$

c) $$\frac {6k}{xy}$$

d) $$\frac {6ky}{x}$$

e) $$\frac {6xy}{k}$$

With this problem solving question it would be easier to plug in numbers.

Let's say that:
K=5
X=1
6=6
Y=10

So the liquid leaks out at a rate of 5l per hour, every litre cost 6$and every hour costs 30$.
If Y= 10 the cost of the liquid per hour (30$) multiplied by Y(10) equals 300. Our target is 300. Plug in the numbers in the answer choices and the answer that yelds 300 will be the right one. A $$\frac {ky}{6x}$$ = 5(10)/6= 8.333333 B $$\frac {6x}{ky}$$ = 6/5(10)= 0.12 C $$\frac {6k}{xy}$$ = 6(5)/10 = 3 D $$\frac {6ky}{x}$$ = 6(5)(10)/1 = 300 CORRECT (we could stop at D but if you have time go ahead) E $$\frac {6xy}{k}$$ = 60/5 = 12 Intern Joined: 28 Oct 2015 Posts: 22 Re: A certain liquid leaks out of a container at the rate of k liters for [#permalink] ### Show Tags 16 Jan 2016, 06:51 Let's say: K=2 X=3 Y=5 leaking every an hour will be 6*2/3 , and after Y hours: (6*2)*5/3. Plugging in our variables we have (K*6*Y)/X. So answer choice is D. Target Test Prep Representative Status: Founder & CEO Affiliations: Target Test Prep Joined: 14 Oct 2015 Posts: 5375 Location: United States (CA) Re: A certain liquid leaks out of a container at the rate of k liters for [#permalink] ### Show Tags 31 Oct 2017, 16:39 zaarathelab wrote: A certain liquid leaks out of a container at the rate of k liters for every x hours. If the liquid costs$6 per liter, what is the cost, in dollars, of the amount of the liquid that will leak out in y hours?

A) $$\frac {ky}{6x}$$

B) $$\frac {6x}{ky}$$

C) $$\frac {6k}{xy}$$

D) $$\frac {6ky}{x}$$

E) $$\frac {6xy}{k}$$

The leak rate is k/x; thus, in y hours, ky/x liters will leak out, which will cost (6)(ky/x) = 6ky/x dollars.

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Manager
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Location: India
Concentration: Technology, General Management
GMAT 1: 660 Q46 V38
GPA: 3.6
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Re: A certain liquid leaks out of a container at the rate of k liters for  [#permalink]

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02 Nov 2017, 20:53
Answer should be D

lost per hour = k/x
lost in y hours = k*y/x
total cost = 6ky/x
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A certain liquid leaks out of a container at the rate of k liters for  [#permalink]

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05 Sep 2018, 22:50
ScottTargetTestPrep wrote:
zaarathelab wrote:
A certain liquid leaks out of a container at the rate of k liters for every x hours. If the liquid costs \$6 per liter, what is the cost, in dollars, of the amount of the liquid that will leak out in y hours?

A) $$\frac {ky}{6x}$$

B) $$\frac {6x}{ky}$$

C) $$\frac {6k}{xy}$$

D) $$\frac {6ky}{x}$$

E) $$\frac {6xy}{k}$$

The leak rate is k/x; thus, in y hours, ky/x liters will leak out, which will cost (6)(ky/x) = 6ky/x dollars.

Hi Scott,

I hope you're well. In an algebraic expression like the above, why wouldn't it be 6k/xy? Isn't y representative of hours? Sorry for the silly question.

A certain liquid leaks out of a container at the rate of k liters for   [#permalink] 05 Sep 2018, 22:50
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# A certain liquid leaks out of a container at the rate of k liters for

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