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A dice is rolled twice. What is the probability that the number in the

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New post 06 Dec 2019, 00:58
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A dice is rolled twice. What is the probability that the number in the second roll will be higher than that in the first roll:

A. 1/4
B. 2/5
C. 3/5
D. 5/12
E. 7/12
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A dice is rolled twice. What is the probability that the number in the  [#permalink]

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New post 08 Dec 2019, 09:09
If we get 6 on the first roll then we have 5 possibilities [5,4,3,2,1] for the second roll.
Similarly if we get 5 on the first roll then we have 4 possibilities for the second roll.
Total probability = (1/6)*(5/6)+(1/6)*(4/6)+(1/6)*(3/6)+(1/6)*(2/6)+(1/6)*(1/6) = 5/12

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A dice is rolled twice. What is the probability that the number in the  [#permalink]

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New post 08 Dec 2019, 13:19
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total possible combinations= 6*6=36

combinations in which both rolls are equal= 6 [(1,1), (2,2)........, (6,6)]

In the remaining rolls (36-6=30), Half of the cases have first roll higher than second one, and Half of the cases have second roll higher than first one.

Number of cases in which second roll will be higher than that in the first roll= 30/2=15

Probability= 15/36= 5/12

ab965 wrote:
A dice is rolled twice. What is the probability that the number in the second roll will be higher than that in the first roll:

A. 1/4
B. 2/5
C. 3/5
D. 5/12
E. 7/12
GMAT Club Bot
A dice is rolled twice. What is the probability that the number in the   [#permalink] 08 Dec 2019, 13:19
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A dice is rolled twice. What is the probability that the number in the

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