carcass
Ok what I mean is this
the first chart is this
The following problem, that is again a weighted average % change problem is this
In the first one I did: Jar A Jar B and then Total NOT Difference. I handle it as the second one. is wrong.
How to recognize in a problem to set a chart as the first one or the second one. I do not see difference but indeed there is difference.
Thanks
The original question asks: "by what percent is the number of jellybeans in B
larger than the number of jellybeans in jar A?" Thus we are interested in Difference/Original=Difference/Jar A.
For example by what percent is 14 more than 10: general formula for percent increase or decrease, (percent change): \(Percent=\frac{Change}{Original}*100\) --> \(Percent=\frac{14-10}{10}*100=40%\) --> 14 is 40% more than 10.
The second question:
Last year, all registered voters in Kumannia voted either for the Revolutionary Party or for the Status Quo Party. This year, the number of revolutionary voters increased 10%, while the number of Status Que voters increased 5%. No other votes were cast. If the number of total voters increased 8%, what fraction of voters voted Revolutionary this year?Now, this question asks about the
ratio of (This year's Revolutionary voters) to (This year's total voters). So, no percent increase (decrease) involved.
SolutionSet the equation for the number of total voters this year: \(1.1R+1.05S=1.08(R+S)\) --> \(2R=3S\)
The question is \(\frac{1.1R}{1.1R+1.05S}=?\) --> \(\frac{1.1R}{1.1R+1.05S}=\frac{110R}{110R+105S}\). Now, as \(2R=3S\) then \(70R=105S\) (multiplying by 35) --> substitute 105S by 70R: \(\frac{110R}{110R+105S}=\frac{110R}{110R+70R}=\frac{11}{18}\)
Hope it's clear.