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07 Jul 2015, 02:47
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (01:55) correct
22%
(01:47)
wrong
based on 265
sessions
History
Date
Time
Result
Not Attempted Yet
A hot dog vendor who sells only hot dogs and soft drinks charges $3 for a hot dog. If the vendor collected $1,000 in total revenue last month, how much does he charge for a soft drink?
(1) The vendor sold twice as many hot dogs as soft drinks last month.
(2) The revenue from hot dog sales last month was 3/4 of the total monthly revenue.
Kudos for a correct solution.
(1) The vendor sold twice as many hot dogs as soft drinks last month.
(2) The revenue from hot dog sales last month was 3/4 of the total monthly revenue.
Kudos for a correct solution.
07 Jul 2015, 03:33
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Last month revenue: \(3*N_h + P_s*N_s = $1000\)... Equation (i)
Statement (1): \(N_h = 2*N_s\)
\(6*N_s + P_s*N_s = $1000\)
\(N_s*(6+P_s)=$1000\)
Possible solutions:
\(N_s = 50, P_s = 14\)
\(N_s = 10, P_s = 94\)
NOT sufficient
Statement (2):\(3*N_h=3/4*$1000\)
\(N_h = $250\)
From Equation (i), \(P_s*N_s = $1000-$750\)
\(P_s*N_s = $250\)
Possible solutions:
\(N_s = 50, P_s = 5\)
\(N_s = 5, P_s = 50\)
NOT sufficient
Statement (1) & Statement (2) together:
\(P_s*N_s = $250, N_s*(6+P_s)=$1000\)
\(6*N_s = 1000 - 250\)
\(6 *N_s = 750\)
\(N_s = 125\)
\(250/P_s = 125\)
\(P_s = 2\)
Sufficient
Answer (C)
Statement (1): \(N_h = 2*N_s\)
\(6*N_s + P_s*N_s = $1000\)
\(N_s*(6+P_s)=$1000\)
Possible solutions:
\(N_s = 50, P_s = 14\)
\(N_s = 10, P_s = 94\)
NOT sufficient
Statement (2):\(3*N_h=3/4*$1000\)
\(N_h = $250\)
From Equation (i), \(P_s*N_s = $1000-$750\)
\(P_s*N_s = $250\)
Possible solutions:
\(N_s = 50, P_s = 5\)
\(N_s = 5, P_s = 50\)
NOT sufficient
Statement (1) & Statement (2) together:
\(P_s*N_s = $250, N_s*(6+P_s)=$1000\)
\(6*N_s = 1000 - 250\)
\(6 *N_s = 750\)
\(N_s = 125\)
\(250/P_s = 125\)
\(P_s = 2\)
Sufficient
Answer (C)
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
Given Kudos: 816
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
07 Jul 2015, 05:11
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Bunuel
Let n be the numbe rof hot dogs sold last month. Let m and p be the number and price of soft drink respectively last month.
Thus, per the question 3n+mp =1000 and p=?
1. Per statement 1, n=2m.
This reduces the above equation to:
1000 = m(6+p) this is still 1 equation with 2 variables. Thus not sufficient.
2. 3n= 0.75*1000 , this gives the value of n=250
Still the above equation 3n+mp=1000, has 2 variables remaining (m,p) but only 1 equation. Thus not sufficient.
Combining 1 and 2,
n=250, n=2m >> m=125
Substituting these values in the main equation, 3n+mp=1000, we get p=2$. Hence C is the correct answer.
