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14 Feb 2011, 17:24
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A jar contains 16 marbles, of which 4 are red, 3 are blue, and the rest are yellow. If 2 marbles are to be selected at random from the jar, one at a time without being replaced, what is the probability that the first marble selected will be red and the second marble selected will be blue?
A. 3/64
B. 1/20
C. 1/16
D. 1/12
E. 1/8
A. 3/64
B. 1/20
C. 1/16
D. 1/12
E. 1/8
14 Feb 2011, 17:47
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banksy
A jar contains 16 marbles, of which 4 are red, 3 are blue, and the rest are yellow. If 2 marbles are to be selected at random from the jar, one at a time without being replaced, what is the probability that the first marble selected will be red and the second marble selected will be blue?
A. 3/64
B. 1/20
C. 1/16
D. 1/12
E. 1/8
A. 3/64
B. 1/20
C. 1/16
D. 1/12
E. 1/8
Note that we want the first marble selected to be red and the second marble selected to be blue.
P=4/16*3/15=1/20.
Answer: B.
17 Feb 2011, 11:19
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banksy
A jar contains 16 marbles, of which 4 are red, 3 are blue, and the rest are yellow. If 2 marbles are to be selected at random from the jar, one at a time without being replaced, what is the probability that the first marble selected will be red and the second marble selected will be blue?
A. 3/64
B. 1/20
C. 1/16
D. 1/12
E. 1/8
A. 3/64
B. 1/20
C. 1/16
D. 1/12
E. 1/8
Its an "and" question so think multiplication.
Let P{a}= P{1st marble is red}= \(\frac{4}{16}\)
P{B}=P{2nd marble is blue}=\(\frac{3}{15}\)
P{A}andp{B}=\(\frac{4}{16}*\frac{3}{15}= \frac{1}{20}\)
Answer B.
