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If 6 is the median of a series of 5 numbers, then it is the third number in the series.

__ __ 6 __ __

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If 2 is the mode, then 2 is the most frequent and thus the first two elements in the series.

2 2 6 __ __

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Since (average) x (quantity) = sum, then (5)(5) = 25 is the sum

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The first three elements total 10. Thus the final two elements must total 15 (25-10 = 15).

For 6 to me the median, it has to be the 3rd element in the list and hence, the next integer needs to be bigger than 6. Which n least case is 7.

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SO, The only two elements that total 15 and that satisfy the conditions are 7 and 8

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Answer:E

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The most common mistake that one needs to avoid here is is to account for this scenario: For 6 to me the median, it has to be the 3rd element in the list and hence, the next integer needs to be bigger than 6. Which n least case is 7.

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