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# A merchandise feedback online portal accords ‘ratings’ to a product by

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Manager
Joined: 10 Feb 2014
Posts: 85
GMAT 1: 690 Q50 V33
A merchandise feedback online portal accords ‘ratings’ to a product by  [#permalink]

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Updated on: 30 Apr 2015, 02:54
3
17
00:00

Difficulty:

95% (hard)

Question Stats:

35% (02:31) correct 65% (02:21) wrong based on 175 sessions

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A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57

Originally posted by itzmyzone911 on 04 Oct 2014, 11:02.
Last edited by itzmyzone911 on 30 Apr 2015, 02:54, edited 1 time in total.
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by  [#permalink]

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04 Mar 2018, 16:04
4
1
Hi All,

This prompt is rather wordy, but it's really just asking us to estimate the value of the fraction. The quirky part is that it does not give us the fraction to work with - it tells us what the fraction should be rounded to.

We're told that the percentage of Unsatisfied customers is close to 57%, so the percentage of Satisfied customers is close to 43%. We're asked for the LEAST possible number of people who could be Satisfied AND fit this percentage data.

2 Satisfied and 2 Unsatisfied = 2/4 = 50%
2 Satisfied and 3 Unsatisfied = 2/5 = 40%
Neither of these percents would round off to 43%, so Answer A is not correct.

3 Satisfied and 3 Unsatisfied = 3/6 = 50%
3 Satisfied and 4 Unsatisfied = 3/7 = over 42.6%
This has to be the answer. The percent rounds to 43%.

Since the question asked for the LEAST number of people, there's no need to check the other answers.

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Rich
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##### General Discussion
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Joined: 04 Jul 2014
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by  [#permalink]

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04 Oct 2014, 23:26
2
itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. Given the fact that the exact percentage of people reported as ‘unsatisfied’ is closest to 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57

~57% unsatisfied . So ~43% satisfied

But 100% should be an integer only and since the above percentages are approximations 100% should be as close as possible to an integer.

Now substitute value

[1] If 43% is 2 what is 100% -> 200/43 is not giving a number which is closest to an integer.

[2] If 43% is 3 what is 100% -> 300/43 [43*7=301] ...therefore closest possible to an integer. [It also satisfies the least possible and hence we need not check for other choices which are greater than 3]

Therefore Ans is B.
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by  [#permalink]

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26 Jan 2018, 10:50
3
1
itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57

Since unsatisfied customers = 57%, satisfied customers = 43%. The difference is 14%. Recall that 1/7 ≈ 14%; thus, the least number of people surveyed is 7, with 4 being unsatisfied and 3 being satisfied. (Note: 4/7 = 0.57143 ≈ 57% and 3/7 = 0.42857 ≈ 43%.)

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Re: A merchandise feedback online portal accords ‘ratings’  [#permalink]

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26 Jan 2018, 11:11
1
JeffTargetTestPrep wrote:
itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57

Since unsatisfied customers = 57%, satisfied customers = 43%. The difference is 14%. Recall that 1/7 ≈ 14%; thus, the least number of people surveyed is 7, with 4 being unsatisfied and 3 being satisfied. (Note: 4/7 = 0.57143 ≈ 57% and 3/7 = 0.42857 ≈ 43%.)

Hi JeffTargetTestPrep - Can I please ask the importance of calculating difference here? I am unable to grasp it?
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Manager
Joined: 23 May 2017
Posts: 236
Concentration: Finance, Accounting
WE: Programming (Energy and Utilities)
Re: A merchandise feedback online portal accords ‘ratings’ to a product by  [#permalink]

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05 Mar 2018, 12:38
1
EMPOWERgmatRichC wrote:
Hi All,

This prompt is rather wordy, but it's really just asking us to estimate the value of the fraction. The quirky part is that it does not give us the fraction to work with - it tells us what the fraction should be rounded to.

We're told that the percentage of Unsatisfied customers is close to 57%, so the percentage of Satisfied customers is close to 43%. We're asked for the LEAST possible number of people who could be Satisfied AND fit this percentage data.

2 Satisfied and 2 Unsatisfied = 2/4 = 50%
2 Satisfied and 3 Unsatisfied = 2/5 = 40%
Neither of these percents would round off to 43%, so Answer A is not correct.

3 Satisfied and 3 Unsatisfied = 3/6 = 50%
3 Satisfied and 4 Unsatisfied = 3/7 = over 42.6%
This has to be the answer. The percent rounds to 43%.

Since the question asked for the LEAST number of people, there's no need to check the other answers.

GMAT assassins aren't born, they're made,
Rich

Thanks Rich. you just made it so simple.
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by  [#permalink]

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24 May 2019, 09:13
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by   [#permalink] 24 May 2019, 09:13
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