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A merchandise feedback online portal accords ‘ratings’ to a product by

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A merchandise feedback online portal accords ‘ratings’ to a product by [#permalink]

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A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57
[Reveal] Spoiler: OA

Last edited by itzmyzone911 on 30 Apr 2015, 01:54, edited 1 time in total.
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by [#permalink]

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itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. Given the fact that the exact percentage of people reported as ‘unsatisfied’ is closest to 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57


~57% unsatisfied . So ~43% satisfied

But 100% should be an integer only and since the above percentages are approximations 100% should be as close as possible to an integer.

Now substitute value

[1] If 43% is 2 what is 100% -> 200/43 is not giving a number which is closest to an integer.

[2] If 43% is 3 what is 100% -> 300/43 [43*7=301] ...therefore closest possible to an integer. [It also satisfies the least possible and hence we need not check for other choices which are greater than 3]

Therefore Ans is B.
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by [#permalink]

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itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57


Since unsatisfied customers = 57%, satisfied customers = 43%. The difference is 14%. Recall that 1/7 ≈ 14%; thus, the least number of people surveyed is 7, with 4 being unsatisfied and 3 being satisfied. (Note: 4/7 = 0.57143 ≈ 57% and 3/7 = 0.42857 ≈ 43%.)

Answer: B
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Re: A merchandise feedback online portal accords ‘ratings’ [#permalink]

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JeffTargetTestPrep wrote:
itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57


Since unsatisfied customers = 57%, satisfied customers = 43%. The difference is 14%. Recall that 1/7 ≈ 14%; thus, the least number of people surveyed is 7, with 4 being unsatisfied and 3 being satisfied. (Note: 4/7 = 0.57143 ≈ 57% and 3/7 = 0.42857 ≈ 43%.)



Answer: B


Hi JeffTargetTestPrep - Can I please ask the importance of calculating difference here? I am unable to grasp it?
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Re: A merchandise feedback online portal accords ‘ratings’   [#permalink] 26 Jan 2018, 10:11
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