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A merchandise feedback online portal accords ‘ratings’ to a product by

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itzmyzone911
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A merchandise feedback online portal accords ‘ratings’ to a product by [#permalink] New post   Updated on: 30 Apr 2015, 02:54
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A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57
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B

Originally posted by itzmyzone911 on 04 Oct 2014, 11:02.
Last edited by itzmyzone911 on 30 Apr 2015, 02:54, edited 1 time in total.
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by [#permalink] New post   04 Mar 2018, 16:04
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Hi All,

This prompt is rather wordy, but it's really just asking us to estimate the value of the fraction. The quirky part is that it does not give us the fraction to work with - it tells us what the fraction should be rounded to.

Since the answer choices are numbers, we have a great opportunity to TEST THE ANSWERS. Instead of randomly pulling numbers off the top of your head, you can use the answers to your advantage. Here's how:

We're told that the percentage of Unsatisfied customers is close to 57%, so the percentage of Satisfied customers is close to 43%. We're asked for the LEAST possible number of people who could be Satisfied AND fit this percentage data.

Let's start with Answer A: 2 people

2 Satisfied and 2 Unsatisfied = 2/4 = 50%
2 Satisfied and 3 Unsatisfied = 2/5 = 40%
Neither of these percents would round off to 43%, so Answer A is not correct.

Answer B: 3 people

3 Satisfied and 3 Unsatisfied = 3/6 = 50%
3 Satisfied and 4 Unsatisfied = 3/7 = over 42.6%
This has to be the answer. The percent rounds to 43%.

Since the question asked for the LEAST number of people, there's no need to check the other answers.

Final Answer:
Show Spoiler
B


GMAT assassins aren't born, they're made,
Rich
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by [#permalink] New post   04 Oct 2014, 23:26
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itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. Given the fact that the exact percentage of people reported as ‘unsatisfied’ is closest to 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57


~57% unsatisfied . So ~43% satisfied

But 100% should be an integer only and since the above percentages are approximations 100% should be as close as possible to an integer.

Now substitute value

[1] If 43% is 2 what is 100% -> 200/43 is not giving a number which is closest to an integer.

[2] If 43% is 3 what is 100% -> 300/43 [43*7=301] ...therefore closest possible to an integer. [It also satisfies the least possible and hence we need not check for other choices which are greater than 3]

Therefore Ans is B.
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by [#permalink] New post   26 Jan 2018, 10:50
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itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57


Since unsatisfied customers = 57%, satisfied customers = 43%. The difference is 14%. Recall that 1/7 ≈ 14%; thus, the least number of people surveyed is 7, with 4 being unsatisfied and 3 being satisfied. (Note: 4/7 = 0.57143 ≈ 57% and 3/7 = 0.42857 ≈ 43%.)

Answer: B
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Re: A merchandise feedback online portal accords ‘ratings’ [#permalink] New post   26 Jan 2018, 11:11
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JeffTargetTestPrep wrote:
itzmyzone911 wrote:
A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?

1. 2
2. 3
3. 12
4. 43
5. 57


Since unsatisfied customers = 57%, satisfied customers = 43%. The difference is 14%. Recall that 1/7 ≈ 14%; thus, the least number of people surveyed is 7, with 4 being unsatisfied and 3 being satisfied. (Note: 4/7 = 0.57143 ≈ 57% and 3/7 = 0.42857 ≈ 43%.)



Answer: B


Hi JeffTargetTestPrep - Can I please ask the importance of calculating difference here? I am unable to grasp it?
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Re: A merchandise feedback online portal accords ‘ratings’ to a product by [#permalink] New post   05 Mar 2018, 12:38
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EMPOWERgmatRichC wrote:
Hi All,

This prompt is rather wordy, but it's really just asking us to estimate the value of the fraction. The quirky part is that it does not give us the fraction to work with - it tells us what the fraction should be rounded to.

Since the answer choices are numbers, we have a great opportunity to TEST THE ANSWERS. Instead of randomly pulling numbers off the top of your head, you can use the answers to your advantage. Here's how:

We're told that the percentage of Unsatisfied customers is close to 57%, so the percentage of Satisfied customers is close to 43%. We're asked for the LEAST possible number of people who could be Satisfied AND fit this percentage data.

Let's start with Answer A: 2 people

2 Satisfied and 2 Unsatisfied = 2/4 = 50%
2 Satisfied and 3 Unsatisfied = 2/5 = 40%
Neither of these percents would round off to 43%, so Answer A is not correct.

Answer B: 3 people

3 Satisfied and 3 Unsatisfied = 3/6 = 50%
3 Satisfied and 4 Unsatisfied = 3/7 = over 42.6%
This has to be the answer. The percent rounds to 43%.

Since the question asked for the LEAST number of people, there's no need to check the other answers.

Final Answer:
Show Spoiler
B


GMAT assassins aren't born, they're made,
Rich


Thanks Rich. you just made it so simple.
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Re: A merchandise feedback online portal accords ratings to a product by [#permalink] New post   01 Jul 2022, 22:58
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Re: A merchandise feedback online portal accords ratings to a product by [#permalink]
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