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D
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29%
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A plane averages 60 miles per hour slower than a second plane. If the slower plane completes a particular trip in three hours, how long will the faster plane take to complete the same trip?
(1) The trip was 1,590 miles.
(2) The slower plane travels at 530 miles per hour.
(1) The trip was 1,590 miles.
(2) The slower plane travels at 530 miles per hour.
12 Apr 2017, 03:51
Kudos
Bookmarks
Speed of faster plane = x, Time = t, Distance = d
Speed of slower plane = x - 60, Timer = 3, Distance = d
t = ?
St1: d = 1590 --> x - 60 = 530 --> t = 1590/590
Sufficient
St2: x - 60 = 530 --> d = 530 * 3 = 1590 --> t = 1590/590
Sufficient
Answer: D
Speed of slower plane = x - 60, Timer = 3, Distance = d
t = ?
St1: d = 1590 --> x - 60 = 530 --> t = 1590/590
Sufficient
St2: x - 60 = 530 --> d = 530 * 3 = 1590 --> t = 1590/590
Sufficient
Answer: D
12 Apr 2017, 05:35
Kudos
Bookmarks
Bunuel
A plane averages 60 miles per hour slower than a second plane. If the slower plane completes a particular trip in three hours, how long will the faster plane take to complete the same trip?
(1) The trip was 1,590 miles.
(2) The slower plane travels at 530 miles per hour.
(1) The trip was 1,590 miles.
(2) The slower plane travels at 530 miles per hour.
Speed1 = Speed2 - 60
Time1 = 3 hrs
Speed1*Time1 = Speed2*Time2 = Distance
We need to find Time2.
Statement 1: Distance = 1590
From Distance and Time1, we will find Speed1.
From Speed1, we will find Speed2.
From Speed2 and Distance, we will find Time2.
Sufficient
Statement 2: Speed1 = 530 mph
From Speed1, we can find Speed2.
We have Speed1, Speed2 and Time1 so we can find Time2.
Sufficient
Answer (D)
