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# A portion of \$6600 is invested at a 5% annual return, while

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A portion of \$6600 is invested at a 5% annual return, while [#permalink]

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12 Feb 2004, 11:08
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A portion of \$6600 is invested at a 5% annual return, while
the remainder is invested at a 3% annual return. If the annual
income from the portion earning a 5% return is twice that of
the other portion, what is the total income from the two
investments after one year?

(A) \$180
(B) \$270
(C) \$300
(D) \$320
(E) \$360

(I do not have the official answer)

Vivek.
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"Start By Doing What Is Necessary ,Then What Is Possible & Suddenly You Will Realise That You Are Doing The Impossible"

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12 Feb 2004, 11:27
B) 270
Let X be the portion invested at 5%
Let (6600 - X) the portion invested at 3%
.05X / .03 * [6600 - X] = 2/1
.05X = .06 * [6600-X]
.05X = 396 - .06X
.11X = 396
X = 3600\$
6600 - X = 3000\$
3600 * .05 + 3000 * .03 = 180 + 90 = 270
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Paul

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12 Feb 2004, 11:32
Excellent ..thanks for the explanation Paul...

Vivek.
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"Start By Doing What Is Necessary ,Then What Is Possible & Suddenly You Will Realise That You Are Doing The Impossible"

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12 Feb 2004, 11:32
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# A portion of \$6600 is invested at a 5% annual return, while

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