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A portion of the 85% solution of chemicals was replaced with

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Re: A portion of the 85% solution of chemicals was replaced with [#permalink]

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New post 24 Jul 2016, 03:03
we could just consider "weight" issue and establish "weight" equation:

(1-N)*(85-40)+N*(20-40)=0
N=9/13
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Re: A portion of the 85% solution of chemicals was replaced with [#permalink]

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New post 29 Aug 2016, 10:38
bmwhype2 wrote:
A portion of the 85% solution of chemicals was replaced with an equal amount of 20% solution of chemicals. As a result, 40% solution of chemicals resulted. What part of the original solution was replaced?

A. 5/13
B. 6/13
C. 9/13
D. 13/9
C. 13/6


Please find the solution as attached.
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Re: A portion of the 85% solution of chemicals was replaced with [#permalink]

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New post 20 Sep 2016, 07:35
I got 9/17
not sure why,

experts please help
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Re: A portion of the 85% solution of chemicals was replaced with [#permalink]

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New post 24 Sep 2016, 19:48
0.85(1-x) + 0.20x = 0.40
0.85 -0.85x + 0.20x = 0.40
-0.65x = -0.45 --> x = 9/13
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A portion of the 85% solution of chemicals was replaced with [#permalink]

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New post 22 Dec 2016, 05:41
KillerSquirrel wrote:

the new ratio is 20:45 = 4:9 ---> meaning that if we had 13ml of 85% solution we now have only 4ml so the part that was replaced is 9/13.

:)


Thanks for the solution but can somebody explain the logic step by step and slowly?

the new ratio is 20:45 = 4:9 ---> meaning that if we had 13ml [ 4x + 9x = 13 and for the sake of the solution x = 1 hence 13 ml ] of 85% solution

[13ml of 85% solution .... what someone should understand by this. If someone tries to find the 0.85 of 13 it will not get int value] we now have only 4ml [how this magic 4 came up] so the part that was replaced is 9/13. [by now totally lost]
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Re: A portion of the 85% solution of chemicals was replaced with [#permalink]

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New post 04 Feb 2018, 14:16
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Re: A portion of the 85% solution of chemicals was replaced with   [#permalink] 04 Feb 2018, 14:16

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