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05 Jun 2018, 22:00
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D
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Difficulty:
25%
(medium)
Question Stats:
78% (01:31) correct
22%
(01:59)
wrong
based on 116
sessions
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A retailer sold toys at a regular selling price of 25% greater than the retailer’s cost to buy the toys. If the retailer reduces the regular selling price by 80%, what is then the loss on each toy sold as a percent of the retailer’s cost?
(A) 25%
(B) 30%
(C) 40%
(D) 75%
(E) 80%
(A) 25%
(B) 30%
(C) 40%
(D) 75%
(E) 80%
05 Jun 2018, 22:24
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A retailer sold toys at a regular selling price of 25% greater than the retailer’s cost to buy the toys. If the retailer reduces the regular selling price by 80%, what is then the loss on each toy sold as a percent of the retailer’s cost?
(A) 25%
(B) 30%
(C) 40%
(D) 75%
(E) 80%
Let Cost Price be = 100
Therefore, the Selling price would be = 125
Now the revised selling price after 80% reduction would be = 125*20%= 25
Therefore loss = Cost Price - Revised selling price => 100-25=75
Now, loss on each toy sold as a percent of the retailer’s cost =( 75/100)*100 = 75%
D is the Answer
(A) 25%
(B) 30%
(C) 40%
(D) 75%
(E) 80%
Let Cost Price be = 100
Therefore, the Selling price would be = 125
Now the revised selling price after 80% reduction would be = 125*20%= 25
Therefore loss = Cost Price - Revised selling price => 100-25=75
Now, loss on each toy sold as a percent of the retailer’s cost =( 75/100)*100 = 75%
D is the Answer
05 Jun 2018, 22:27
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Solution
Given:
- • Retailer sold toys at a regular selling price of 25% greater than his cost
To find:
- • The loss percentage of the retailer, if he reduces the regular selling price by 80%
Approach and Working:
If we assume the cost for the retailer to be x, then we can say
- • The regular selling price = 1.25x
As the retailer reduces the regular selling price by 80%,
- • The new selling price after the reduction = 1.25x * 0.2 = 0.25x
Therefore, after reduction in price,
- • Cost to the retailer = x
• Selling price for the retailer = 0.25x
• Loss percentage = \(\frac{(x – 0.25x)}{x} * 100\)= 75%
Hence, the correct answer is option D.
Answer: D
