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A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so

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Math Expert
Joined: 02 Sep 2009
Posts: 50039
A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so  [#permalink]

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05 Feb 2018, 06:23
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Difficulty:

25% (medium)

Question Stats:

76% (01:35) correct 24% (02:08) wrong based on 83 sessions

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A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so that the longer dimension will be 4 inches. The length of the enlarged shorter dimension will be

(A) 5/2 inches

(B) 3 inches

(C) 27/8 inches

(D) 21/8 inches

(E) none of these

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Joined: 16 Sep 2017
Posts: 21
Re: A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so  [#permalink]

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05 Feb 2018, 06:54
1
Shorter length =(15/8)*(8/5)=3

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Joined: 05 Dec 2016
Posts: 246
Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
Re: A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so  [#permalink]

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05 Feb 2018, 07:16
sides ratio = 5/2 : 15/8 = 4/3 (big/small)
Let x be shorter side of enlarged snapshot
4/3=4/x
x=3
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Joined: 22 May 2016
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A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so  [#permalink]

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05 Feb 2018, 21:02
1
Bunuel wrote:
A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so that the longer dimension will be 4 inches. The length of the enlarged shorter dimension will be

(A) 5/2 inches

(B) 3 inches

(C) 27/8 inches

(D) 21/8 inches

(E) none of these

You can use a multiplier / scale factor.

The $$\frac{5}{2}$$-inch side is longer than $$\frac{15}{8}$$-inch side.

$$\frac{5}{2}$$ inches is enlarged to 4 inches.

$$\frac{5}{2}*k = 4$$
The scale factor k =
$$\frac{4}{\frac{5}{2}} = 4 * \frac{2}{5} = \frac{8}{5}$$

Enlarged length of shorter dimension is (scale factor) * (original length)
$$\frac{8}{5}* \frac{15}{8} = 3$$ inches

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Re: A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so  [#permalink]

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06 Feb 2018, 17:56
Quote:
A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so that the longer dimension will be 4 inches. The length of the enlarged shorter dimension will be

(A) 5/2 inches

(B) 3 inches

(C) 27/8 inches

(D) 21/8 inches

Assuming the length-and-width ratio of the snapshot will be maintained after enlargement, we can set up the following proportion, where x is the width of the enlarged snapshot:

(15/8)/(5/2) = x/4

x(5/2) = 4(15/8)

5x/2 = 15/2

5x = 15

x = 3

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Intern
Joined: 14 Dec 2016
Posts: 11
Re: A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so  [#permalink]

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07 Feb 2018, 13:24
isn't this supposed to be 2.5(5/2) moving to 4 i.e. addition of 1.5 to it. the same applies for shorter side also i.e. 15/8 (1.875) +1.5 =3.375 = 27/8 - option c
Re: A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so &nbs [#permalink] 07 Feb 2018, 13:24
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A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so

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