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11 Aug 2016, 11:26
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Difficulty:
55%
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Question Stats:
69% (02:34) correct
31%
(01:55)
wrong
based on 13
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A sphere with radius x shrinks by a% in volume. What is the new radius of the resulting sphere, in terms of x and a?
A) x^3 * \(\sqrt{(a/100)}\)
B) x^3 * \(\sqrt{(1 - (a/100))}\)
C) 4/3 * π * x^3 * \(\sqrt{(1 - (a/100))}\)
D) x^3 * \(\sqrt{(100 / (100 - a))}\)
E) 4/3 * π * x^3 * \(\sqrt{(100 / (100 - a))}\)
Please develop in detail your answer so that we can all follow it.
A) x^3 * \(\sqrt{(a/100)}\)
B) x^3 * \(\sqrt{(1 - (a/100))}\)
C) 4/3 * π * x^3 * \(\sqrt{(1 - (a/100))}\)
D) x^3 * \(\sqrt{(100 / (100 - a))}\)
E) 4/3 * π * x^3 * \(\sqrt{(100 / (100 - a))}\)
Please develop in detail your answer so that we can all follow it.
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11 Aug 2016, 11:33
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EBITDA
A sphere with radius x shrinks by a% in volume. What is the new radius of the resulting sphere, in terms of x and a?
A) x^3 * \(\sqrt{(a/100)}\)
B) x^3 * \(\sqrt{(1 - (a/100))}\)
C) 4/3 * π * x^3 * \(\sqrt{(1 - (a/100))}\)
D) x^3 * \(\sqrt{(100 / (100 - a))}\)
E) 4/3 * π * x^3 * \(\sqrt{(100 / (100 - a))}\)
Please develop in detail your answer so that we can all follow it.
A) x^3 * \(\sqrt{(a/100)}\)
B) x^3 * \(\sqrt{(1 - (a/100))}\)
C) 4/3 * π * x^3 * \(\sqrt{(1 - (a/100))}\)
D) x^3 * \(\sqrt{(100 / (100 - a))}\)
E) 4/3 * π * x^3 * \(\sqrt{(100 / (100 - a))}\)
Please develop in detail your answer so that we can all follow it.
Hi EBITDA,
What's the source of this question? I ask because the GMAT does not require test-takers to know the formula for the volume of a sphere. In a question like this, you would be provided with that formula: Volume = (4/3)πr³
11 Aug 2016, 11:40
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Initial radius of the sphere is x
Volume =4/3* π* x^3
Volume is shrinked by a%
=> new volume = (100-a)/100*(4/3* π* x^3)
let the new radius be y
new volume =4/3* π* y^3
=>4/3* π* y^3= (100-a)/100*(4/3* π* x^3)
=> y^3= ((100-a)/100)* x^3
=>y^3= (1-a/100)* x^3
Is'nt this the solution.
Can somebody verify this.
thanks in advance.
Volume =4/3* π* x^3
Volume is shrinked by a%
=> new volume = (100-a)/100*(4/3* π* x^3)
let the new radius be y
new volume =4/3* π* y^3
=>4/3* π* y^3= (100-a)/100*(4/3* π* x^3)
=> y^3= ((100-a)/100)* x^3
=>y^3= (1-a/100)* x^3
Is'nt this the solution.
Can somebody verify this.
thanks in advance.
