iamschnaider wrote:
A tank is filled with gasoline to a depth of exactly 2 feet. The tank is a cylinder resting horizontally on its side, with its circular ends oriented vertically. The inside of the tank is exactly 6 feet long. What is the volume of gasoline in the tank?
1) The inside of the tank is exactly 4 feet in diameter.
2) The top surface of the gasoline forms a rectangle that has an area of 24 square feet.
From
OG 2016 (question 86 DS)
I get why 1 works, but the main qualm I have about 2 is how we can be sure that the 4 feet resulting from the square is a diameter of the circle ie. how we know that it fills the tank exactly up to halfway.
Hi,
i agree with you however we still can find the answer ..
we can find the chord/diameter of the circular end as 4..
now we have depth as 2, length as 6 and width as 4 but the volume will vary depending on what the dia would be..
there could be two scenarios..
1) where the center is below the chord... that is greater than 2\(\sqrt{3}\)..
eq becomes \(2^2+(2\sqrt{3}+r)^2=r^2\)
r comes out negative so not possible.
2) where the center is above the chord... that is greater than 2\(\sqrt{3}\).. r can be found so suff..
eq becomes \(2^2+(2\sqrt{3}-r)^2=r^2\)
.
Though i understood the logic i am confused at the first place as how u got 2√3 in the beginning..
close
