pintukr
A test was conducted in a school such that students get 1 mark for a correct answer and loses a third of a mark for a wrong answer. If a student' scored 105 marks and he attempted all the questions, which of the following cannot be the total number of questions in the test?
A. 185
B. 195
C. 205
D. 245
E. 285
(adapted from gmatfree)Hi
ThatDudeKnows Regor60Let Total number of questions = N
Total correct answers = c.............(+1 for every correct answer)
Total wrong answers = N-c.........(-1/3 for every wrong answer)
then, Marks scored = 105 = c*1 - (N-c)/3
105 = c - (N-c)/3
105 = (4c - N)/3
315 = 4c - N
c = (315 + N) / 4
Need to note that c can only be an integer >=0
Putting N = 185, c = (315+185)/4 = 125
Putting N = 195, c = (315+195)/4 = 127.5 (Not Possible, since c is not an integer)
Putting N = 205, c = (315+205)/4 = 130
Putting N = 245, c = (315+245)/4 = 140
Putting N = 285, c = (315+285)/4 = 150
(B) is the correct answer You changed the answer choices from those that were originally in your post!!
In looking at the question and answer choices as they originally appeared prior to the edit, I think the following approach is more efficient.
105 obviously works. If we get one more question correct, we need to get three more questions incorrect.
We therefore have 105+4n where n is any whole number.
Check the answer choices.
185 works.
195 doesn't.
Answer choice B.
Note that 4n must be even, so 105+4n must be even. This is how
Regor60 very quickly knew that the even answer choices that were in the original post wouldn't work.