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17 Feb 2015, 09:23
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:18) correct
19%
(01:09)
wrong
based on 113
sessions
History
Date
Time
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A train ride from Birdville to Baytown costs $6.95 more than does a bus ride from Birdville to Baytown. Together, the cost of one train ride and one bus ride is $9.45. What is the cost of a bus ride from Birdville to Baytown?
A. $1.25
B. $2.50
C. $4.10
D. $4.70
E. $8.20
Kudos for a correct solution.
A. $1.25
B. $2.50
C. $4.10
D. $4.70
E. $8.20
Kudos for a correct solution.
17 Feb 2015, 09:55
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Bookmarks
The question states the following:
$6.95+Bus Ride=Train Ride
The question also states that:
Train Ride + Bus Ride = $9.45
If we combine both of the statements we will see that:
$6.95+Bus Ride (i.e. the train ride) + Bus Ride =$9.45
To solve for how much a bus ride will cost, we go through the following steps:
Bus Ride =B
6.95+B+B=$9.45
6.95+2B=9.45
2B=9.45-6.95
2B=2.5
B=2.5/2
B=1.25
Finally, looking back at the question, it asks what is the cost of a bus ride which would equal to $1.25
$6.95+Bus Ride=Train Ride
The question also states that:
Train Ride + Bus Ride = $9.45
If we combine both of the statements we will see that:
$6.95+Bus Ride (i.e. the train ride) + Bus Ride =$9.45
To solve for how much a bus ride will cost, we go through the following steps:
Bus Ride =B
6.95+B+B=$9.45
6.95+2B=9.45
2B=9.45-6.95
2B=2.5
B=2.5/2
B=1.25
Finally, looking back at the question, it asks what is the cost of a bus ride which would equal to $1.25
17 Feb 2015, 21:33
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Hi All,
Most Test Takers would solve this with an algebraic approach, which is fine. The math is fairly straight-forward and the work isn't too difficult. However, if you're looking to maximize your performance on Test Day, you have to consider if THAT approach is actually fastest... You might find that TESTing THE ANSWERS is actually faster...
We're told that a train ride between two cities costs $6.95 MORE than a bus ride between those same two cities. We're then told that the cost of 1 train ride + 1 bus ride = $9.45. We're asked for the cost of one BUS ride between those two cities.
Logically, since the train ride is almost $7 MORE than the bus ride and the total is $9.45, the bus ride has to be a relatively small number. Looking at the answer choices, it would have to be either Answer A or Answer B. We can TEST either one - if it's a match, then we're done. If it's NOT a match, then the other answer will be correct.
Since Answer B looks "nicer", we can start there.
IF....
The bus ride = $2.50
The train ride is $6.95 MORE = $9.45
One of each = $2.50 + $9.45 = MORE than $9.45
This answer is TOO BIG.
There's only one answer that's left AND is smaller.
Final Answer:
GMAT assassins aren't born, they're made,
Rich
Most Test Takers would solve this with an algebraic approach, which is fine. The math is fairly straight-forward and the work isn't too difficult. However, if you're looking to maximize your performance on Test Day, you have to consider if THAT approach is actually fastest... You might find that TESTing THE ANSWERS is actually faster...
We're told that a train ride between two cities costs $6.95 MORE than a bus ride between those same two cities. We're then told that the cost of 1 train ride + 1 bus ride = $9.45. We're asked for the cost of one BUS ride between those two cities.
Logically, since the train ride is almost $7 MORE than the bus ride and the total is $9.45, the bus ride has to be a relatively small number. Looking at the answer choices, it would have to be either Answer A or Answer B. We can TEST either one - if it's a match, then we're done. If it's NOT a match, then the other answer will be correct.
Since Answer B looks "nicer", we can start there.
IF....
The bus ride = $2.50
The train ride is $6.95 MORE = $9.45
One of each = $2.50 + $9.45 = MORE than $9.45
This answer is TOO BIG.
There's only one answer that's left AND is smaller.
Final Answer:
GMAT assassins aren't born, they're made,
Rich
