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28 Jul 2019, 04:18
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Difficulty:
55%
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Question Stats:
69% (02:37) correct
31%
(02:34)
wrong
based on 67
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A vessel ( capacity 10 ltrs) is filled entirely with petrol and kerosene in the ratio 3:2. Two ltrs of this solution is removed and replaced with 2 ltrs of kerosene. This procedure is repeated thrice. Find the % of petrol in the resulting solution.
A) 20%
B) 30.72%
C) 40.23%
D) 52.15%
E) 63.2%
nick1816
Rahulihavenoclue
A) 20%
B) 30.72%
C) 40.23%
D) 52.15%
E) 63.2%
(B)
Rahulihavenoclue
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28 Jul 2019, 04:38
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Initial volume of the petrol in vessel=(3/5)*10=6
Let volume of the petrol in vessel after 3 replacements=V
\(V=6(1-\frac{2}{10})^3\)
\(V=6*(\frac{4}{5})^3\)
V= 3.072L
% of petrol in the resulting solution= \(\frac{3.072}{10}*100=30.72\)%
Let volume of the petrol in vessel after 3 replacements=V
\(V=6(1-\frac{2}{10})^3\)
\(V=6*(\frac{4}{5})^3\)
V= 3.072L
% of petrol in the resulting solution= \(\frac{3.072}{10}*100=30.72\)%
shivansh9307
A vessel ( capacity 10 ltrs) is filled entirely with petrol and kerosene in the ratio 3:2. Two ltrs of this solution is removed and replaced with 2 ltrs of kerosene. This procedure is repeated thrice. Find the % of petrol in the resulting solution.
A) 20%
B) 30.72%
C) 40.23%
D) 52.15%
E) 63.2%
nick1816
Rahulihavenoclue
A) 20%
B) 30.72%
C) 40.23%
D) 52.15%
E) 63.2%
(B)
Rahulihavenoclue
28 Jul 2019, 08:32
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Bookmarks
oohhh...nick1816 Thanks for the solution mate..
it took me a lot of time calculating Petrol amount after each iteration, though finally i made the correct option. But saw your post. This is good..
it took me a lot of time calculating Petrol amount after each iteration, though finally i made the correct option. But saw your post. This is good..
