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The first four terms of the sequence are: x, 5x/2, 25x/4, 125x/8.
We want to know if 125x/8 - 5x/2 = 105x/8 is an integer. 105 and 8 share no common factors. Therefore x must be a multiple of 8 in order for the difference to yield an integer value.

(1) x = 12*k = 2^3 * 3 * k (k > 0) :

We can test two values to see that Statement 1 is not sufficient. If x = 24, then 105x/8 yields an integer. If x = 36 then, no (105*36 is not divisible by 8 - can be deduced from prime factorization).

(2) x = 56 *q = 7 * 2^3 * q (q>0) : x has 8 as a factor. As such, 105x/8 will always be divisible by 8. Sufficient.

Answer: B
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inconnu99
The first four terms of the sequence are: x, x/2, 25x/4, 125x/8.
We want to know if 125x/8 - 5x/2 = 105x/8 is an integer. 105 and 8 share no common factors. Therefore x must be a multiple of 8 in order for the difference to yield an integer value.

(1) x = 12*k = 2^3 * 3 * k (k > 0) :

We can test two values to see that Statement 1 is not sufficient. If x = 24, then 105x/8 yields an integer. If x = 36 then, no (105*36 is not divisible by 8 - can be deduced from prime factorization).

(2) x = 56 *q = 7 * 2^3 * q (q>0) : x has 8 as a factor. As such, 105x/8 will always be divisible by 8. Sufficient.

Answer: B

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inconnu99
The first four terms of the sequence are: x, x/2, 25x/4, 125x/8.
We want to know if 125x/8 - 5x/2 = 105x/8 is an integer. 105 and 8 share no common factors. Therefore x must be a multiple of 8 in order for the difference to yield an integer value.

(1) x = 12*k = 2^3 * 3 * k (k > 0) :

We can test two values to see that Statement 1 is not sufficient. If x = 24, then 105x/8 yields an integer. If x = 36 then, no (105*36 is not divisible by 8 - can be deduced from prime factorization).

(2) x = 56 *q = 7 * 2^3 * q (q>0) : x has 8 as a factor. As such, 105x/8 will always be divisible by 8. Sufficient.

Answer: B

How come the second term here is x/2? Because in the question it says, "five time greater than half the preceding term".
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