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28 Feb 2016, 09:45
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Alan buys 4 TVs, a 26 inch, a 28 inch, a 30 inch, and a 32 inch, for his new house. Each TV costs $200 more than the size below it. Alan spends a total of $3,400. How much would he have spent if he had bought only the 28 inch and 30 inch TVs?
A. 850
B. 1,100
C. 1,700
D. 2,550
E. 3,400
A. 850
B. 1,100
C. 1,700
D. 2,550
E. 3,400
28 Feb 2016, 13:13
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Bunuel
Alan buys 4 TVs, a 26 inch, a 28 inch, a 30 inch, and a 32 inch, for his new house. Each TV costs $200 more than the size below it. Alan spends a total of $3,400. How much would he have spent if he had bought only the 28 inch and 30 inch TVs?
A. 850
B. 1,100
C. 1,700
D. 2,550
E. 3,400
A. 850
B. 1,100
C. 1,700
D. 2,550
E. 3,400
The problem stated is in AP.
Avg price = 3400/4 = 850
Since in AP , 850*2 = 1700 (Sum of 1st and 4th term or 2nd term and third term)
IMO C
To add more.
1 + 2 + 3 + 4 + ....+98 + 99 + 100
100+1 = 99+2 = 98 + 3 = 97 + 4 and goes on till 51+50
This is how the formula N(N+1) divided by 2 got derived.
03 Mar 2016, 03:23
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Bunuel
Alan buys 4 TVs, a 26 inch, a 28 inch, a 30 inch, and a 32 inch, for his new house. Each TV costs $200 more than the size below it. Alan spends a total of $3,400. How much would he have spent if he had bought only the 28 inch and 30 inch TVs?
A. 850
B. 1,100
C. 1,700
D. 2,550
E. 3,400
A. 850
B. 1,100
C. 1,700
D. 2,550
E. 3,400
Assume the cost of the least sized (26 Inch) TV = x
Cost of 28 inches TV = x + 200
Cost of 30 inches TV = x + 400
Cost of 32 inches TV = x + 600
Total cost = 4x + 1200 = 3400
Therefore x = 2200/4 = 550
Price of 28inch + 30 inch = 750 + 950 = 1700
Option C
