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24 Mar 2019, 23:45
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Difficulty:
75%
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Question Stats:
50% (02:32) correct
50%
(00:59)
wrong
based on 10
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All of David's telephone numbers have the form 555-abc-defg, where a, b, c, d, e, f, and g are distinct digits and in increasing order, and none is either 0 or 1. How many different telephone numbers can David have?
(A) 1
(B) 2
(C) 7
(D) 8
(E) 9
(A) 1
(B) 2
(C) 7
(D) 8
(E) 9
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25 Mar 2019, 01:02
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We can choose only from 2,3,4,5,6,7,8,9 I.e for seven places we can choose from 8 numbers
So different numbers david have= 8C7=8
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So different numbers david have= 8C7=8
Posted from my mobile device
25 Mar 2019, 01:11
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A, b, c, d, e, f & g are seven digits in increasing order. Neither of which is 0 or 1. So, if a=2, g=8 and when a=3,g=9.
Total number of combinations=2
Posted from my mobile device
Total number of combinations=2
Posted from my mobile device
