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Difficulty:
35%
(medium)
Question Stats:
77%
(02:39)
correct 23%
(02:56)
wrong
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An international health organization collected global data regarding a certain disease for each of 14 consecutive years (Y1 – Y14). The graph shows the annual numbers of cases, countries, countries with local cases (i.e., cases for which the infection was contracted within the country), and countries with non-local cases (i.e., cases for which the infection was contracted outside of the country).
From each drop-down menu, select the option that creates the most accurate statement according to the information provided.
The percent increase in the number of cases of the disease from Y9 to Y12 was, to the nearest 10%, .
The average (arithmetic mean) of the numbers of countries with local cases from Y1 to Y5 was, to the nearest 5 countries, .
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The percent increase in the number of cases of the disease from Y9 to Y12 was, to the nearest 10%, _________.
Solution: For Y9, the number of cases if 200,000 and for Y12 the number of cases is 600,000. To calculate the percent increase in the number of cases: Increase = 600,000 - 200,000 = 400,000. % Increase = ( 400,000 / 200,000 ) * 100 = ( 4 / 2 ) * 100 = 200 %
Part 2:
The average (arithmetic mean) of the numbers of countries with local cases from Y1 to Y5 was, to the nearest 5 countries, _________.
Solution: Y1 - 51 countries Y2 - 50 countries Y3 - 39 countries Y4 - 40 countries Y5 - 55 countries Mean = ( 51 + 50 + 39 + 40 + 55 ) / 5 = 235 / 5 = 47. Closest option choice nearest to 5 is 45.
Lets say the answer is 58%,the nearest ten percent would be 60% i.e round up and if the answer lets say is 51-55 %,round down to 50%,basically it depends on the units digits of the number. 5 or less, round down,6 to 9 round up. Hope this clarifies
The percent increase in the number of cases of the disease from Y9 to Y12 was, to the nearest 10%, _________.
Solution: For Y9, the number of cases if 200,000 and for Y12 the number of cases is 600,000. To calculate the percent increase in the number of cases: Increase = 600,000 - 200,000 = 400,000. % Increase = ( 400,000 / 200,000 ) * 100 = ( 4 / 2 ) * 100 = 200 %
Part 2:
The average (arithmetic mean) of the numbers of countries with local cases from Y1 to Y5 was, to the nearest 5 countries, _________.
Solution: Y1 - 51 countries Y2 - 50 countries Y3 - 40 countries Y4 - 40 countries Y5 - 45 countries Mean = ( 51 + 50 + 40 + 40 + 45 ) / 5 = 226 / 5 ~ 45.2 Closest option choice nearest to 5 is 45.
Question 1 is straight forward, number of cases of the disease from Y9 (200) to Y12(600) was, so {(600-200)/200} *100= 200% In Question 2, data moves between 50 and 40 so average should be in between, there is one value in the given answer choice; 45 and it is our answer
I want to know how come the country in Y5 is 55(highlighted), i can see it as 45. Can you please revisit RutujaDeshmukh19.
RutujaDeshmukh19
Part 1:
The percent increase in the number of cases of the disease from Y9 to Y12 was, to the nearest 10%, _________.
Solution: For Y9, the number of cases if 200,000 and for Y12 the number of cases is 600,000. To calculate the percent increase in the number of cases: Increase = 600,000 - 200,000 = 400,000. % Increase = ( 400,000 / 200,000 ) * 100 = ( 4 / 2 ) * 100 = 200 %
Part 2:
The average (arithmetic mean) of the numbers of countries with local cases from Y1 to Y5 was, to the nearest 5 countries, _________.
Solution: Y1 - 51 countries Y2 - 50 countries Y3 - 39 countries Y4 - 40 countries Y5 - 55 countries Mean = ( 51 + 50 + 39 + 40 + 55 ) / 5 = 235 / 5 = 47. Closest option choice nearest to 5 is 45.
I want to know how come the country in Y5 is 55(highlighted), i can see it as 45. Can you please revisit RutujaDeshmukh19.
RutujaDeshmukh19
Part 1:
The percent increase in the number of cases of the disease from Y9 to Y12 was, to the nearest 10%, _________.
Solution: For Y9, the number of cases if 200,000 and for Y12 the number of cases is 600,000. To calculate the percent increase in the number of cases: Increase = 600,000 - 200,000 = 400,000. % Increase = ( 400,000 / 200,000 ) * 100 = ( 4 / 2 ) * 100 = 200 %
Part 2:
The average (arithmetic mean) of the numbers of countries with local cases from Y1 to Y5 was, to the nearest 5 countries, _________.
Solution: Y1 - 51 countries Y2 - 50 countries Y3 - 39 countries Y4 - 40 countries Y5 - 55 countries Mean = ( 51 + 50 + 39 + 40 + 55 ) / 5 = 235 / 5 = 47. Closest option choice nearest to 5 is 45.
for que 2 ..a more visual and intuitive solution should be more helpful. the number of countries for y1 and y2 are more than 45 and for y3 and y4 are less than 45 ..and then there is 45(approx.) for Y5