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# At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr.

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Manager
Joined: 24 Feb 2020
Posts: 160
Location: Italy
WE: Analyst (Investment Banking)
At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr.  [#permalink]

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31 Mar 2020, 03:55
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Difficulty:

35% (medium)

Question Stats:

71% (02:01) correct 29% (01:47) wrong based on 45 sessions

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At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr. At 4:30 P.M. train B leaves the station on a parallel route and traveling at 150 mi/hr. How far away from the station will the second train overtake the first train?

A. 250
B. 500
C. 750
D. 800
E. 1500
DS Forum Moderator
Joined: 19 Oct 2018
Posts: 1832
Location: India
Re: At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr.  [#permalink]

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31 Mar 2020, 21:12
1
Relative distance between 2 trains at 4:30PM = 100*2.5 = 250 miles

Relative speed = 150-100 = 50 miles/hr

Time taken by train B to overtake train A = 250/50= 5 hrs

Total distance travelled by train B= 150*5= 750 miles

Ravixxx wrote:
At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr. At 4:30 P.M. train B leaves the station on a parallel route and traveling at 150 mi/hr. How far away from the station will the second train overtake the first train?

A. 250
B. 500
C. 750
D. 800
E. 1500
GMATWhiz Representative
Joined: 07 May 2019
Posts: 700
Location: India
Re: At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr.  [#permalink]

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02 Apr 2020, 04:17
1
Ravixxx wrote:
At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr. At 4:30 P.M. train B leaves the station on a parallel route and traveling at 150 mi/hr. How far away from the station will the second train overtake the first train?

A. 250
B. 500
C. 750
D. 800
E. 1500

Solution:

o Train A has already travelled 2.5 hr when train B started.
o Distance traveled by A in first 2.5 hr = $$100*2.5 = 250$$ miles
o When train B overtook A, both the train must have traveled same distance.
o Let t be the time when train B overtook A.
 Distance covered by A = $$250 + 100*t$$
 Distance covered by B = $$150*t$$
o $$150*t = 250 + 100*t$$
o $$150*t – 100*t =250$$
o $$50*t = 250$$
o $$t = 5 hr$$
o Total distance travelled by travel B = $$150*5 = 750$$ miles.
Hence, the correct answer is Option C.
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Re: At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr.   [#permalink] 02 Apr 2020, 04:17