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31 Mar 2020, 04:55
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At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr. At 4:30 P.M. train B leaves the station on a parallel route and traveling at 150 mi/hr. How far away from the station will the second train overtake the first train?
A. 250
B. 500
C. 750
D. 800
E. 1500
A. 250
B. 500
C. 750
D. 800
E. 1500
31 Mar 2020, 22:12
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Relative distance between 2 trains at 4:30PM = 100*2.5 = 250 miles
Relative speed = 150-100 = 50 miles/hr
Time taken by train B to overtake train A = 250/50= 5 hrs
Total distance travelled by train B= 150*5= 750 miles
Relative speed = 150-100 = 50 miles/hr
Time taken by train B to overtake train A = 250/50= 5 hrs
Total distance travelled by train B= 150*5= 750 miles
Ravixxx
At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr. At 4:30 P.M. train B leaves the station on a parallel route and traveling at 150 mi/hr. How far away from the station will the second train overtake the first train?
A. 250
B. 500
C. 750
D. 800
E. 1500
A. 250
B. 500
C. 750
D. 800
E. 1500
02 Apr 2020, 05:17
Kudos
Bookmarks
Ravixxx
At 2:00 P.M. a train A leaves a station traveling at 100 mi/hr. At 4:30 P.M. train B leaves the station on a parallel route and traveling at 150 mi/hr. How far away from the station will the second train overtake the first train?
A. 250
B. 500
C. 750
D. 800
E. 1500
A. 250
B. 500
C. 750
D. 800
E. 1500
Solution:
- o Train A has already travelled 2.5 hr when train B started.
o Distance traveled by A in first 2.5 hr = \(100*2.5 = 250\) miles
o When train B overtook A, both the train must have traveled same distance.
o Let t be the time when train B overtook A.
- Distance covered by A = \(250 + 100*t\)
Distance covered by B = \(150*t\)
o \(150*t – 100*t =250\)
o \(50*t = 250\)
o \(t = 5 hr\)
o Total distance travelled by travel B = \(150*5 = 750\) miles.
