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At a certain restaurant, the price of a sandwich is $ 4.00 more than the price of a cup of coffee. If the price of a sandwich and a cup of coffee is $ 7.35, including a sales tax of 5%, what is the price of a cup of coffee, EXCLUDING the sales tax?
A. $ 1.50
B. $ 3.00
C. $ 4.00
D. $ 5.50
E. $ 7.00
A. $ 1.50
B. $ 3.00
C. $ 4.00
D. $ 5.50
E. $ 7.00
06 Jan 2016, 12:00
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Let the price of sandwhich = S
price of coffee = C
S= C+4
=> S - C = 4 --1
the price of a sandwich and a cup of coffee is $ 7.35, including a sales tax of 5%,
1.05(S+C) = 7.35
=> S+C = 7 --2
From equations 1 and 2, we get
S=5.5$
C= 1.5$
Answer A
price of coffee = C
S= C+4
=> S - C = 4 --1
the price of a sandwich and a cup of coffee is $ 7.35, including a sales tax of 5%,
1.05(S+C) = 7.35
=> S+C = 7 --2
From equations 1 and 2, we get
S=5.5$
C= 1.5$
Answer A
17 Feb 2017, 09:35
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Bunuel
At a certain restaurant, the price of a sandwich is $ 4.00 more than the price of a cup of coffee. If the price of a sandwich and a cup of coffee is $ 7.35, including a sales tax of 5%, what is the price of a cup of coffee, EXCLUDING the sales tax?
A. $ 1.50
B. $ 3.00
C. $ 4.00
D. $ 5.50
E. $ 7.00
A. $ 1.50
B. $ 3.00
C. $ 4.00
D. $ 5.50
E. $ 7.00
On scanning the options, only option A will give a total amount less than 7.35$.i.e 1.5+5.5=7. Rest of the options will give an amount greater than 7.35$ and that's impossible given the total cost of sandwich and coffee inclusive of tax is 7.35$.
Hence A.
