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Updated on: 10 Jul 2019, 05:45
Originally posted by rohan2345 on 19 May 2017, 02:22.
Last edited by Sajjad1994 on 10 Jul 2019, 05:45, edited 1 time in total.
Last edited by Sajjad1994 on 10 Jul 2019, 05:45, edited 1 time in total.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
75% (00:51) correct
25%
(01:11)
wrong
based on 53
sessions
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Time
Result
Not Attempted Yet
By dividing 21 into 1, the fraction 1/21 can be written as a repeating decimal: 0.476190476190 . . . where the block of digits 476190 repeats. What is the 54th digit following the decimal point?
(A) 0
(B) 4
(C) 6
(D) 7
(E) 9
(A) 0
(B) 4
(C) 6
(D) 7
(E) 9
Source: Nova GMAT
Difficulty Level: 550
Difficulty Level: 550
19 May 2017, 02:35
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6 digits(476190) repeats itself. Thus, the digits represent:
4 - (6n+1)th term
7 - (6n+2)th term
6 - (6n+3)th term
1 - (6n+4)th term
9 - (6n+5)th term
0 - (6n+6)th term
Now 54th = 8*6+6. Hence the 54th digit is 0.
4 - (6n+1)th term
7 - (6n+2)th term
6 - (6n+3)th term
1 - (6n+4)th term
9 - (6n+5)th term
0 - (6n+6)th term
Now 54th = 8*6+6. Hence the 54th digit is 0.
19 May 2017, 03:09
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So basically a 6-digit code is being repeated. We have to find which of the 6 digits will appear at the 54th place.
Clearly we can see that 54 is divisible by 6. This means digit will be the 6th (last one) of the code. Which is '0'.
Hence answer is A.
Clearly we can see that 54 is divisible by 6. This means digit will be the 6th (last one) of the code. Which is '0'.
Hence answer is A.
