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# Can anyone list all the postive integers as in the attached

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Manager
Joined: 29 Apr 2003
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Can anyone list all the postive integers as in the attached [#permalink]

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24 Aug 2003, 08:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Can anyone list all the postive integers as in the attached?

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Intern
Joined: 04 Jul 2003
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24 Aug 2003, 09:07
Hello, i am new to this but i'll like to try and answer.

I think the answer is 11.

i worked it out this way -

two prime factor products 4 C 2 = 6
three prime factor products 4 C 3 = 4
four prime factor products 4 C 4 = 1

the answer is 6+4+1 = 11.

all the positive integers are

5*7 = 35 , 5*11 = 55, 5*13 =65, 7*11=77, 7*13 = 91, 11*13= 143.

5*7*11 = 385, 5*7*13= 455, 5*11*13=715, 7*11*13=1001

5*7*13*11=5005

please correct the mistakes if any.

Thank You.

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CEO
Joined: 15 Aug 2003
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24 Aug 2003, 15:03
tzec76 wrote:
Can anyone list all the postive integers as in the attached?

Product can be a combination of 2 numbers , 3 numbers or 4 numbers.

Therefore, find the combination of 4 numbers taken 2 at a time, 4 numbers taken 3 at a time and 4 numbers taken 4 at a time

4C2 + 4C3+4C4 = 6 + 4+1 =11

Thanks
Praetorian

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Manager
Joined: 10 Jun 2003
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25 Aug 2003, 08:40
Yes, wonderful example of how a seemingly confusing problem can be sooooooo simple if you take 20 seconds to think about it and relate it to basic combinations.

Great!
_________________

Sept 3rd

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25 Aug 2003, 08:40
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