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# Can anyone show the steps to find both the ways to

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Manager
Joined: 29 Apr 2003
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Can anyone show the steps to find both the ways to [#permalink]

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18 Aug 2003, 13:00
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Can anyone show the steps to find both the ways to distribute total no. of bills is equal to the ways if at least one person get \$3.
Manager
Joined: 14 Aug 2003
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18 Aug 2003, 16:00
lets calculate A:
7=1+1+5=1+2+4=1+3+3=2+2+3=> there are 4*3! such ways
lets calculate B:
7=7+0+0=6+1+0=5+2+0=5+1+1=4+3+0 (so on) => there are 10*3! such ways

B>A
Manager
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19 Aug 2003, 06:58
Column A = Column B.

The answer given is not quite correct.
Manager
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19 Aug 2003, 10:02
then i must have misunderstood B... ive calculated the number of ways of distributing 7 bills, but without considering the condition "each one receives 1 bill"... my bad, sorry... taking that into consideration, A=B
Manager
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23 Aug 2003, 04:25

Column A

3+3+1
3+2+2
3+1+3

Column B

1+3+3
1+2+4
1+1+5
23 Aug 2003, 04:25
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