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Re: Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. [#permalink]
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Kudos
Solve using option ,
Option E out straightaway .
Start with middle value to be considered .
consider option D , then 10*8=80 and 5*4=20 but difference is not 2.
Consider option C , then 10*6=60 and 5*8=40 ... difference 8-6=2 .. hence this is answer
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Re: Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. [#permalink]
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Let # 5 once package=x , # 10 once package =y
so we have 5x+10Y =100 ---1
and x=y+2 ---2
equating equation 1 & 2 we get y = 6
Hence answer is C
Thanks,
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Re: Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. [#permalink]
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Bunuel wrote:
Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have?

A. 2
B. 4
C. 6
D. 8
E. 10

Kudos for a correct solution.


MANHATTAN GMAT OFFICIAL SOLUTION:

Let a = the number of 5-ounce packages.
Let b = the number of 10-ounce packages.

Carina has 100 ounces of coffee: 5a + 10b = 100
She has two more 5-ounce packages than 10-ounce packages: a = b + 2

Combine the equations by substituting the value of a from equation 2 into equation 1.
5(b + 2) + 10b = 100
b = 6.

Answer: C.
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Re: Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. [#permalink]
Bunuel wrote:
Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have?

A. 2
B. 4
C. 6
D. 8
E. 10

Kudos for a correct solution.

It is easier to plug in values in the option to get the answer.
A 4*5+2*10=40
B 6*5+4*10=70
C 8*5+6*10=100
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Re: Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. [#permalink]
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Re: Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. [#permalink]
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