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Clarissa will create her summer reading list by randomly choosing 4 bo
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12 Jun 2017, 15:01

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Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

Clarissa will create her summer reading list by randomly choosing 4 bo
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12 Jun 2017, 16:11

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AbdurRakib wrote:

Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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27 Jun 2017, 15:26

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AbdurRakib wrote:

Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6 B. 40 C. 210 D. 5,040 E. 151,200

Take the task of creating the reading list and break it into stages.

Stage 1: Select a book to read 1st There are 10 books to choose from. So, we can complete stage 1 in 10 ways

Stage 2: Select a book to read 2nd There are 9 books remaining to choose from (since we already chose a book in stage 1). So, we can complete stage 2 in 9 ways

Stage 3: Select a book to read 3rd There are 8 books remaining to choose from. So, we can complete stage 3 in 8 ways

Stage 4: Select a book to read 4th There are 7 books remaining to choose from. So, we can complete stage 4 in 7 ways

By the Fundamental Counting Principle (FCP), we can complete all 4 stages (and thus create a reading list) in (10)(9)(8)(7) ways (= 5040 ways)

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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08 Aug 2017, 23:45

AbdurRakib wrote:

Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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15 Nov 2017, 17:21

3

AbdurRakib wrote:

Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6 B. 40 C. 210 D. 5,040 E. 151,200

Since the order of the books in her list matters, we use permutation. Thus, the number of ways 4 books can be chosen and ordered from 10 books is 10P4 = 10!/(10-4)! = 10 x 9 x 8 x 7 = 5,040.

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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26 Nov 2017, 03:47

genxer123 wrote:

AbdurRakib wrote:

Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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26 Nov 2017, 03:54

ScottTargetTestPrep wrote:

AbdurRakib wrote:

Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6 B. 40 C. 210 D. 5,040 E. 151,200

Since the order of the books in her list matters, we use permutation. Thus, the number of ways 4 books can be chosen and ordered from 10 books is 10P4 = 10!/(10-4)! = 10 x 9 x 8 x 7 = 5,040.

Answer: D

and if the order didn't matter the answer would be 210 ? like this ? -- > 10! / 4!(10-4)! =210

Clarissa will create her summer reading list by randomly choosing 4 bo
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26 Nov 2017, 07:03

dave13 wrote:

ScottTargetTestPrep wrote:

AbdurRakib wrote:

Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6 B. 40 C. 210 D. 5,040 E. 151,200

Since the order of the books in her list matters, we use permutation. Thus, the number of ways 4 books can be chosen and ordered from 10 books is 10P4 = 10!/(10-4)! = 10 x 9 x 8 x 7 = 5,040.

Answer: D

and if the order didn't matter the answer would be 210 ? like this ? -- > 10! / 4!(10-4)! =210

"She will list the books in the order in which they are chosen""--Order matters here ...So 10P4

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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30 Jul 2018, 22:27

generis wrote:

AbdurRakib wrote:

Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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30 Jul 2018, 23:04

Solution

Given:

• Clarissa will choose 4 books from the 10 books. • She will list the books in the order in which they are chosen.

To find:

• The number of different possible lists.

Approach and Working:

• She is first selecting 4 books and then listing them. • This is same as selectin and then arrangement. o Hence, this a permutation question. • Thus, total ways= \(^{10}P_4\)= 5040.

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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13 Dec 2018, 02:53

She chooses 4 out of 10 books = 10C4 Now, _ _ _ _ the 4 books chosen can be arranged in 4! ways therefore, number of different lists = 10C4 * 4! = 5040

Re: Clarissa will create her summer reading list by randomly choosing 4 bo
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28 Dec 2019, 23:52

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