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# Clarissa will create her summer reading list by randomly choosing 4 bo

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Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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12 Jun 2017, 15:01
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35% (medium)

Question Stats:

67% (01:13) correct 33% (01:18) wrong based on 1582 sessions

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Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

The Official Guide for GMAT Review 2018

Practice Question
Problem Solving
Question No.: 140
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Joined: 22 May 2016
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Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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12 Jun 2017, 16:11
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AbdurRakib wrote:
Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

The Official Guide for GMAT Review 2018

Practice Question
Problem Solving
Question No.: 140

Using the fundamental counting principle (or permutation, because order matters -- she's listing them in their order chosen).

She chooses 4 books: __ * __ * __ * __

For her first choice she has 10 books to choose from; then she has nine books; then eight; and then seven.

10 * 9 * 8 * 7 = 5040

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Posts: 4217
Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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27 Jun 2017, 15:26
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AbdurRakib wrote:
Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

Take the task of creating the reading list and break it into stages.

Stage 1: Select a book to read 1st
There are 10 books to choose from. So, we can complete stage 1 in 10 ways

Stage 2: Select a book to read 2nd
There are 9 books remaining to choose from (since we already chose a book in stage 1).
So, we can complete stage 2 in 9 ways

Stage 3: Select a book to read 3rd
There are 8 books remaining to choose from. So, we can complete stage 3 in 8 ways

Stage 4: Select a book to read 4th
There are 7 books remaining to choose from. So, we can complete stage 4 in 7 ways

By the Fundamental Counting Principle (FCP), we can complete all 4 stages (and thus create a reading list) in (10)(9)(8)(7) ways (= 5040 ways)

Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. So, be sure to learn it.

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Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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29 Jun 2017, 00:09
4
4 books can be chosen as 10C4 ways. = 210 ways
Total list of 4 books = 4!
Therefore, total list of possible selection = 210 *4! = 210 *24 =5,040.
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Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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08 Aug 2017, 23:45
AbdurRakib wrote:
Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

The Official Guide for GMAT Review 2018

Practice Question
Problem Solving
Question No.: 140

as the order is important here, so its a Permutation case. So arranging 4 books out of 10 books is
$$10_P_4$$ = 5040

Option D
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Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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15 Nov 2017, 17:21
AbdurRakib wrote:
Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

Since the order of the books in her list matters, we use permutation. Thus, the number of ways 4 books can be chosen and ordered from 10 books is 10P4 = 10!/(10-4)! = 10 x 9 x 8 x 7 = 5,040.

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Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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26 Nov 2017, 03:47
genxer123 wrote:
AbdurRakib wrote:
Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

The Official Guide for GMAT Review 2018

Practice Question
Problem Solving
Question No.: 140

Using the fundamental counting principle (or permutation, because order matters -- she's listing them in their order chosen):

For her first book she has 10 to choose from, then nine, than eight, then seven.

10 * 9 * 8* 7 = 5040

Hello. I dont understand one thing I did so 10! / 4! (10-6)! = 210 so I chose 210 why its D
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Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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26 Nov 2017, 03:54
ScottTargetTestPrep wrote:
AbdurRakib wrote:
Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

Since the order of the books in her list matters, we use permutation. Thus, the number of ways 4 books can be chosen and ordered from 10 books is 10P4 = 10!/(10-4)! = 10 x 9 x 8 x 7 = 5,040.

and if the order didn't matter the answer would be 210 ? like this ? -- > 10! / 4!(10-4)! =210
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Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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26 Nov 2017, 07:03
dave13 wrote:
ScottTargetTestPrep wrote:
AbdurRakib wrote:
Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

Since the order of the books in her list matters, we use permutation. Thus, the number of ways 4 books can be chosen and ordered from 10 books is 10P4 = 10!/(10-4)! = 10 x 9 x 8 x 7 = 5,040.

and if the order didn't matter the answer would be 210 ? like this ? -- > 10! / 4!(10-4)! =210

"She will list the books in the order in which they are chosen""--Order matters here ...So 10P4
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Joined: 16 Nov 2016
Posts: 268
Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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30 Jul 2018, 22:27
generis wrote:
AbdurRakib wrote:
Clarissa will create her summer reading list by randomly choosing 4 books from the 10 books approved for summer reading. She will list the books in the order in which they are chosen. How many different lists are possible?

A. 6
B. 40
C. 210
D. 5,040
E. 151,200

The Official Guide for GMAT Review 2018

Practice Question
Problem Solving
Question No.: 140

Using the fundamental counting principle (or permutation, because order matters -- she's listing them in their order chosen):

For her first book she has 10 to choose from, then nine, than eight, then seven.

10 * 9 * 8* 7 = 5040

Hi,

so if order didn't matter the answer would be...

10!/4!(10-4)! = 210??
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Joined: 04 Jan 2015
Posts: 3209
Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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30 Jul 2018, 23:04

Solution

Given:
• Clarissa will choose 4 books from the 10 books.
• She will list the books in the order in which they are chosen.

To find:
• The number of different possible lists.
Approach and Working:

• She is first selecting 4 books and then listing them.
• This is same as selectin and then arrangement.
o Hence, this a permutation question.
• Thus, total ways= $$^{10}P_4$$= 5040.

Hence, option D is the correct answer.

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Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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30 Jul 2018, 23:07
EgmatQuantExpert,

so if order didn't matter then the answer would be...10!/4!(10-4)! = 210??
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Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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30 Jul 2018, 23:12
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1
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Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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13 Dec 2018, 02:53
She chooses 4 out of 10 books = 10C4
Now, _ _ _ _ the 4 books chosen can be arranged in 4! ways
therefore, number of different lists = 10C4 * 4! = 5040
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Re: Clarissa will create her summer reading list by randomly choosing 4 bo  [#permalink]

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28 Dec 2019, 23:52
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Re: Clarissa will create her summer reading list by randomly choosing 4 bo   [#permalink] 28 Dec 2019, 23:52
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