GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 16 Jan 2019, 04:19

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in January
PrevNext
SuMoTuWeThFrSa
303112345
6789101112
13141516171819
20212223242526
272829303112
Open Detailed Calendar
• ### The winning strategy for a high GRE score

January 17, 2019

January 17, 2019

08:00 AM PST

09:00 AM PST

Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL.
• ### Free GMAT Strategy Webinar

January 19, 2019

January 19, 2019

07:00 AM PST

09:00 AM PST

Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

# D01-29

Author Message
TAGS:

### Hide Tags

VP
Status: It's near - I can see.
Joined: 13 Apr 2013
Posts: 1363
Location: India
GMAT 1: 480 Q38 V22
GPA: 3.01
WE: Engineering (Consulting)

### Show Tags

18 Oct 2018, 04:58
I think this is a high-quality question and I agree with explanation. Great question as always.
_________________

"Do not watch clock; Do what it does. KEEP GOING."

Manager
Joined: 09 Jun 2014
Posts: 218
Location: India
Concentration: General Management, Operations
Schools: Tuck '19

### Show Tags

31 Oct 2018, 22:01
Bunuel wrote:
Official Solution:

Mac can finish the job in $$M$$ days: the rate of Mac is $$\frac{1}{M}$$ job/day;

Jack can finish the job in $$J$$ days: the rate of Jack is $$\frac{1}{J}$$ job/day;

After working together for $$T$$ days, Mac left and Jack alone worked to complete the remaining work in $$R$$ days, hence Mac worked for $$T$$ days only and did $$\frac{T}{M}$$ part of the job while Jack worked for $$T+R$$ days and did $$\frac{T+R}{J}$$ part of the job;

Since Mac and Jack completed an equal amount of work (so half of the job each) then $$\frac{T}{M}=\frac{1}{2}$$ and $$\frac{T+R}{J}=\frac{1}{2}$$. So, $$T=\frac{M}{2}$$ and $$T=\frac{J}{2}-R$$, therefore $$\frac{M}{2}=\frac{J}{2}-R$$, which gives $$J=M+2R$$.

(1) $$M = 20$$ days. Not sufficient, we still need the value of $$R$$.

(2) $$R = 10$$ days. Not sufficient, we still need the value of $$M$$.

(1)+(2) $$J=M+2R=20+2*10=40$$. Sufficient.

Can you please suggest,what was your line of thinking ..I took a longer approach and got confused at the end...

Here is my approach,

Mac's Work =1/M
Jacks' = 1/J

When both work for T days work done = ((1/M) + (1/J))*T
Remaining work = 1 - {(M+J)/MJ}*T

Now work done by jack= T+R days..
So I would make acomplex equution equation work done by Jack and Mac and this would really confuse me spotting R and T
Manager
Joined: 09 Jun 2014
Posts: 218
Location: India
Concentration: General Management, Operations
Schools: Tuck '19

### Show Tags

31 Oct 2018, 22:06
prabsahi wrote:
Bunuel wrote:
Official Solution:

Mac can finish the job in $$M$$ days: the rate of Mac is $$\frac{1}{M}$$ job/day;

Jack can finish the job in $$J$$ days: the rate of Jack is $$\frac{1}{J}$$ job/day;

After working together for $$T$$ days, Mac left and Jack alone worked to complete the remaining work in $$R$$ days, hence Mac worked for $$T$$ days only and did $$\frac{T}{M}$$ part of the job while Jack worked for $$T+R$$ days and did $$\frac{T+R}{J}$$ part of the job;

Since Mac and Jack completed an equal amount of work (so half of the job each) then $$\frac{T}{M}=\frac{1}{2}$$ and $$\frac{T+R}{J}=\frac{1}{2}$$. So, $$T=\frac{M}{2}$$ and $$T=\frac{J}{2}-R$$, therefore $$\frac{M}{2}=\frac{J}{2}-R$$, which gives $$J=M+2R$$.

(1) $$M = 20$$ days. Not sufficient, we still need the value of $$R$$.

(2) $$R = 10$$ days. Not sufficient, we still need the value of $$M$$.

(1)+(2) $$J=M+2R=20+2*10=40$$. Sufficient.

Can you please suggest,what was your line of thinking ..I took a longer approach and got confused at the end...

Here is my approach,

Mac's Work =1/M
Jacks' = 1/J

When both work for T days work done = ((1/M) + (1/J))*T
Remaining work = 1 - {(M+J)/MJ}*T

Now work done by jack= T+R days..
So I would make acomplex equution equation work done by Jack and Mac and this would really confuse me spotting R and T

My main question is how did you take the hint from this question while reading that you have to use this approach..you line of thought
Manager
Joined: 09 Jun 2014
Posts: 218
Location: India
Concentration: General Management, Operations
Schools: Tuck '19

### Show Tags

31 Oct 2018, 22:20
Bunuel wrote:
Mac can finish a job in $$M$$ days and Jack can finish the same job in $$J$$ days. After working together for $$T$$ days, Mac left and Jack alone worked to complete the remaining work in $$R$$ days. If Mac and Jack completed an equal amount of work, how many days would have it taken Jack to complete the entire job working alone?

(1) $$M = 20$$ days

(2) $$R = 10$$ days

Here is my understanding now after screwing up the question

We see Mac works for T days and Jack works for T+R days and another important thing to notice is they complete half of the work each.Now Rate * Time = Work done..This means for Jack 1/J (T+R) = 1/M * (T)=1/2 Now total number of days which jack will take is (T+R)..If you see equation in red you can calculate T=2M and the same u can substitute in 1/J(2M+R)

Press Kudos if it helps!!
Intern
Joined: 03 Jun 2018
Posts: 1

### Show Tags

14 Nov 2018, 07:58
Hi Leonsandcastle332

I believe we are using the W=RT formula. As Bunuel said:
Mac takes M days to do the job so in one day he completes 1/M part of the job. This is the rate.
He works for T days (Time). Therefore, the amount of work he completes in T days is : T*1/M (Time* Rate)

Intern
Joined: 24 Feb 2018
Posts: 35
Location: India
GPA: 3.35
WE: Military Officer (Military & Defense)

### Show Tags

15 Nov 2018, 06:19
I think this is a high-quality question and I agree with explanation.
Re D01-29 &nbs [#permalink] 15 Nov 2018, 06:19

Go to page   Previous    1   2   [ 26 posts ]

Display posts from previous: Sort by

# D01-29

Moderators: chetan2u, Bunuel

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.