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Equilateral triangle is inscribed in a circle. If length of arc ABC is

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Equilateral triangle is inscribed in a circle. If length of arc ABC is  [#permalink]

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New post Updated on: 14 Oct 2018, 05:26
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Equilateral triangle is inscribed in a circle. If length of arc ABC is 2pi, what is the radius of the circle?

(A) 1
(B) 3/2
(C) 2
(D) 5/3
(E) 3

Originally posted by banksy on 05 Mar 2011, 07:50.
Last edited by generis on 14 Oct 2018, 05:26, edited 1 time in total.
Edited the OA
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Re: Equilateral triangle is inscribed in a circle. If length of arc ABC is  [#permalink]

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New post 05 Mar 2011, 08:16
banksy wrote:
164 Equilateral triangle is inscribed in a circle. If length of arc ABC is 2pi, what is the radius of the circle?
(A) 1
(B) 3/2
(C) 2
(D) 5/3
(E) 3


Arc ABC is \(\frac{2}{3}\) of the circumference (as ABC is equilateral triangle then (arc AB)=(arc BC)=(arc AC), so (arc AB)+(arc BC)=(arc ABC)=2/3 of circumference, so \(arc \ ABC=2\pi\) basically means that the circumference is \(3\pi\) --> \(circumference=2\pi{r}=3\pi\) --> \(r=\frac{3}{2}\).

Answer: B.

Similar question: geometry-circle-triangle-from-mba-com-97393.html
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Re: Equilateral triangle is inscribed in a circle. If length of arc ABC is  [#permalink]

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New post Updated on: 05 Mar 2011, 08:51
Yep, thanks Bunuel.
But I don't understand why it is not possible to use another method to solve it....
it drives me crazy cos I don't understand what is wrong with it...please look..

I used formula:
Circumference of sector= (angle in front of the sector/ 360) * 2*pi*R

so if we know that ABC equilateral, so all angles=60 and all circumferences in front of A ,B and C are same. so if circumference in front of 2 angles = 2pi, so circumference in front of one angle is pi.
so
pi= 60/360*2pi*R
so pi=1/6*2pi*R
so pi=1/3pi*R
R=3....

i hope it is clear what I wrote here.
so what is wrong with it?

Originally posted by banksy on 05 Mar 2011, 08:28.
Last edited by banksy on 05 Mar 2011, 08:51, edited 1 time in total.
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Re: Equilateral triangle is inscribed in a circle. If length of arc ABC is  [#permalink]

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New post 05 Mar 2011, 08:37
1
banksy wrote:
Yep, thanks Bunuel.
But I don't understand why it is not possible to use another method to solve it....
it drives me crazy cos I don't understand what is wrong with it...please look..

I used formula:
Circumference of sector= (angle in front of the sector/ 360) * 2*pi*R

so if we know that ABC equilateral, so all angles=60 and all circumferences in front of A ,B and C are same. so if circumference in front of 2 angles = 2pi, so circumference in front of one angle is pi.
so
pi= 60/360*2pi*R
so pi=1/6*2pi*R
so pi=1/3pi*R
R=3....

i hope it is clean what I wrote here.
so what is wrong with it?


In your formula 60 degrees is the measure of the inscribed angle and you should use the measure of the central angle which is twice the inscribed angle so 120 degrees.

Check this: math-circles-87957.html

Arc Length The formula the arc measure is: \(L=2\pi{r}\frac{C}{360}\), where C is the central angle of the arc in degrees. Recall that \(2\pi{r}\) is the circumference of the whole circle, so the formula simply reduces this by the ratio of the arc angle to a full angle (360). By transposing the above formula, you solve for the radius, central angle, or arc length if you know any two of them.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: Equilateral triangle is inscribed in a circle. If length of arc ABC is  [#permalink]

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New post 05 Mar 2011, 08:41
oh, now it is clear)thank you very much!!!=)))
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Re: Equilateral triangle is inscribed in a circle. If length of arc ABC is  [#permalink]

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New post 12 Oct 2018, 05:42
Bunuel wrote:
banksy wrote:
164 Equilateral triangle is inscribed in a circle. If length of arc ABC is 2pi, what is the radius of the circle?
(A) 1
(B) 3/2
(C) 2
(D) 5/3
(E) 3


Arc ABC is \(\frac{2}{3}\) of the circumference (as ABC is equilateral triangle then (arc AB)=(arc BC)=(arc AC), so (arc AB)+(arc BC)=(arc ABC)=2/3 of circumference, so \(arc \ ABC=2\pi\) basically means that the circumference is \(3\pi\) --> \(circumference=2\pi{r}=3\pi\) --> \(r=\frac{3}{2}\).

Answer: B.

Similar question: http://gmatclub.com/forum/geometry-circ ... 97393.html


Bunuel
i think the official answer is wrong. It should be B but it says C.
regards
GMAT Club Bot
Re: Equilateral triangle is inscribed in a circle. If length of arc ABC is   [#permalink] 12 Oct 2018, 05:42
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Equilateral triangle is inscribed in a circle. If length of arc ABC is

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