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Exam Pack IR doubt [#permalink]
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30 Dec 2014, 09:05
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Can any one give detail solution of second question? Please explain how I will think and do these questions quickly. Get Kudos
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Re: Exam Pack IR doubt [#permalink]
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30 Dec 2014, 11:34
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Hi Rajibuddin, If I were low on time and just had to eyeball, I would guess C (Section C) based on where the dots are concentrated. You can see that most of the students in Section C tend to study for fewer hours than students in other sections. However, you could also do the math fairly quickly to determine which Section had the lowest average (remember, the average will be the total number of hours studied/11 students in each section). Therefore, you can simply add the total number of hours studied by each student in each section and determine which section had the lowest number. You don't need to do the division since they will all be divided by the same denominator of 11. Section A: 1*2 + 2*2 + 3*3 + 4*1 + 5*2 + 8*1 = 37 hours Section B: 1*1 + 2*3 + 3*1 + 4*4 + 5*1 + 6*1 = 37 hours Section C: 1*2 + 2*4 + 3*4 + 4*1 = 26 hours Therefore, the answer would be Section C had the smallest average reported time spent studying during the week. Hope this helps!

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Re: Exam Pack IR doubt [#permalink]
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30 Dec 2014, 11:46
How stupid I am! I totally concentrated on the wrong exis. I concentrated on Yxis. Thank you for the reply. It is easy now. Actually we don't need to calculate anything here. By the if the questions asked about the average from yxis, how would you solve it?
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Re: Exam Pack IR doubt [#permalink]
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21 Dec 2015, 05:53
i got a similar one in one of mock test, only it was about types of therapies and highest/lowest no of people benefiting from it.
good one

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Re: Exam Pack IR doubt [#permalink]
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30 Jan 2017, 06:15
hopeful101candidate wrote: Hi Rajibuddin, If I were low on time and just had to eyeball, I would guess C (Section C) based on where the dots are concentrated. You can see that most of the students in Section C tend to study for fewer hours than students in other sections. However, you could also do the math fairly quickly to determine which Section had the lowest average (remember, the average will be the total number of hours studied/11 students in each section). Therefore, you can simply add the total number of hours studied by each student in each section and determine which section had the lowest number. You don't need to do the division since they will all be divided by the same denominator of 11. Section A: 1*2 + 2*2 + 3*3 + 4*1 + 5*2 + 8*1 = 37 hours Section B: 1*1 + 2*3 + 3*1 + 4*4 + 5*1 + 6*1 = 37 hours Section C: 1*2 + 2*4 + 3*4 + 4*1 = 26 hours Therefore, the answer would be Section C had the smallest average reported time spent studying during the week. Hope this helps! I know its a simple question but can anybody explain how to get the answer to the first question . To find the median preparation time we need to arrange the preparation time in increasing order then find the central term. how do we arrive at 3 using this method?
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Re: Exam Pack IR doubt [#permalink]
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04 Feb 2017, 12:45
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central term is (33 +1) / 2 = 17th term First arrange the data in nondecreasing order, since many terms have equal value. term 15 > 1 Hr term 614 > 2 Hrs term 1522 > 3 Hrs > this range contains central term term 2328 > 4 Hrs term 2931 > 5 Hrs term 32 > 6 Hrs term 33 > 8 Hrs So here 17th term is 3 hrs

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Re: Exam Pack IR doubt [#permalink]
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10 Feb 2017, 00:36
stne wrote: hopeful101candidate wrote: Hi Rajibuddin, If I were low on time and just had to eyeball, I would guess C (Section C) based on where the dots are concentrated. You can see that most of the students in Section C tend to study for fewer hours than students in other sections. However, you could also do the math fairly quickly to determine which Section had the lowest average (remember, the average will be the total number of hours studied/11 students in each section). Therefore, you can simply add the total number of hours studied by each student in each section and determine which section had the lowest number. You don't need to do the division since they will all be divided by the same denominator of 11. Section A: 1*2 + 2*2 + 3*3 + 4*1 + 5*2 + 8*1 = 37 hours Section B: 1*1 + 2*3 + 3*1 + 4*4 + 5*1 + 6*1 = 37 hours Section C: 1*2 + 2*4 + 3*4 + 4*1 = 26 hours Therefore, the answer would be Section C had the smallest average reported time spent studying during the week. Hope this helps! I know its a simple question but can anybody explain how to get the answer to the first question . To find the median preparation time we need to arrange the preparation time in increasing order then find the central term. how do we arrive at 3 using this method? Responding to a pm: Quote: to find the median reported time , I have to arrange the reported times in increasing order then find the central term.
1 has been reported 5 times 2 has been reported 9 times 3 has been reported 8 times 4  6 times 5  3 times 6  1 time 8 1 time
You are correct here. 'Reported studying time' is the same as 'number of hours studied per week' on the graph. So 1 hr has been reported by 5 people so it appears 5 times. 2 hrs has been reported by 9 people so it appears 9 times and so on... 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, ... etc The median of these reported times will be the middle value i.e. the 17th term. That term will be 3.
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