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01 Oct 2019, 21:05
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C
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Difficulty:
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Question Stats:
67% (02:13) correct
33%
(02:17)
wrong
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Ezra pays $0.75 each time he takes a public transport to reach his school. Students who frequently use this service may instead purchase token each month for $13 and then pay $0.30 per each ride. If Ezra need to take the bus twice a day for K days next month and will not use the bus on any other day, what is the least possible value of K for which Ezra will save money by using the token?
(A) 10
(B) 12
(C) 15
(D) 18
(E) 28
01 Oct 2019, 22:41
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Cost of ride per trip of bus ride without monthly pass=$0.75
Cost of ride per trip after paying $13 monthly pass =$0.3
We are to determine the minimum number of days, k, that Ezra has to take the bus using a token in order to make a saving.
0.75*2k > 13 + 0.3*2k
1.5k - 0.6k >13
0.9k>13
k>14.444
The minimum possible number of days for Ezra to make a saving using the bus pass has to be 15.
The answer is therefore C.
Cost of ride per trip after paying $13 monthly pass =$0.3
We are to determine the minimum number of days, k, that Ezra has to take the bus using a token in order to make a saving.
0.75*2k > 13 + 0.3*2k
1.5k - 0.6k >13
0.9k>13
k>14.444
The minimum possible number of days for Ezra to make a saving using the bus pass has to be 15.
The answer is therefore C.
01 Oct 2019, 23:25
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Since Ezra takes bus twice a day total money spent without the token for travel f ‘k’ days = 0.75*2*k
If token is taken then total money spent for travel ‘k’ days = 13 + 0.3*2*k
Now as per question to save money while using token
0.75*2*k > 13 + 0.3*2*k
1.5k – 0.6k > 13 [k > 0]
0.9k > 13
k > 14.4
Answer (C).
If token is taken then total money spent for travel ‘k’ days = 13 + 0.3*2*k
Now as per question to save money while using token
0.75*2*k > 13 + 0.3*2*k
1.5k – 0.6k > 13 [k > 0]
0.9k > 13
k > 14.4
Answer (C).
