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Bunuel
f(x) = x^2 - x. For which of the following values of a is f(a) ≥ f(8)?

I. a = -7
II. a = -8
III a = -9

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


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f(8) = 56

f(-7) = 49 +7 = 56.

Rest is > 56.

Answer E
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Bunuel
f(x) = x^2 - x. For which of the following values of a is f(a) ≥ f(8)?

I. a = -7
II. a = -8
III a = -9

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


Kudos for a correct solution.

f(x) = x^2 - x => x(x-1)

f(8) = 8*7 =56

1) f(-7) = -7*-8 = 56
2) f(-8) = -8*-9 = 72
3) f(-9) = -9*-10 = 90

Hence Option E
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Bunuel
f(x) = x^2 - x. For which of the following values of a is f(a) ≥ f(8)?

I. a = -7
II. a = -8
III a = -9

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


Kudos for a correct solution.

\(f(x) = x^2 - x\)
\(f(8) = 8^2 - 8 = 56\)

Test statement: f(a) >= 56

\(f(-7) = -7^2 - (-7) = 56 >= 56\) VALID
\(f(-8) = -8^2 - (-8) = 72 >= 56\) VALID
\(f(-9) = -9^2 - (-9) = 90 >= 56\) VALID

OA should be E
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Bunuel
f(x) = x^2 - x. For which of the following values of a is f(a) ≥ f(8)?

I. a = -7
II. a = -8
III a = -9

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

Beginning with the given f(8) function, you should see that \(f(8)=8^2-8=64-8=56\)

And then do the same for the three other possible values:

I. f(−7) means put -7 wherever you see the x: \((-7)^2-(-7)=49+7=56\), so f(-7) = f(8).

II. f(−8) means put -8 wherever you see the x: \((-8)^2-(-8)=64+8=72\), so f(-8) > f(8).

III. f(−9) means put -9 wherever you see the x: \((-9)^2-(-9)=81+9=90\), so f(-9) > f(8)

Since all three functions satisfy the question, the correct answer is E.
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Bunuel
f(x) = x^2 - x. For which of the following values of a is f(a) ≥ f(8)?

I. a = -7
II. a = -8
III a = -9

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III

f(8) = 8^2 - 8 = 64 - 8 = 56

Let’s analyze each answer choice:

I. a = -7

f(-7) = (-7)^2 - (-7) = 49 + 7 = 56. Yes, f(-7) ≥ f(8) because 56 ≥ 56.

II. a = - 8

f(-8) = (-8)^2 - (-8) = 64 + 8 = 72. Yes, f(-8) ≥ f(8) because 72 ≥ 56.

III. a = -9

f(-9) = (-9)^2 - (-9) = 81 + 9 = 90. Yes, f(-9) ≥ f(8) because 90 ≥ 56.

Answer: E
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Bunuel
f(x) = x^2 - x. For which of the following values of a is f(a) ≥ f(8)?

I. a = -7
II. a = -8
III a = -9

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III

f(8) = 8^2 - 8 = 64 - 8 = 56

Let’s analyze each answer choice:

I. a = -7

f(-7) = (-7)^2 - (-7) = 49 + 7 = 56. Yes, f(-7) ≥ f(8) because 56 ≥ 56.

II. a = - 8

f(-8) = (-8)^2 - (-8) = 64 + 8 = 72. Yes, f(-8) ≥ f(8) because 72 ≥ 56.

III. a = -9

f(-9) = (-9)^2 - (-9) = 81 + 9 = 90. Yes, f(-9) ≥ f(8) because 90 ≥ 56.

Answer: E
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