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22 Nov 2019, 03:33
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D
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Difficulty:
35%
(medium)
Question Stats:
73% (01:25) correct
27%
(01:57)
wrong
based on 56
sessions
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For each of the last 5 years, the population of a colony of beetles increased by 8 percent of the preceding year's population. If P represents the current population of the colony, which of the following best represents the population 5 years ago, in terms of P?
A. \((5)(1.08 P^{-1})\)
B. \((1.08)^{-5}P^{-1}\)
C. \((1.08P)^{-5}\)
D. \((1.08)^{-5}P\)
E. \((1.08)^{-5}P^5\)
A. \((5)(1.08 P^{-1})\)
B. \((1.08)^{-5}P^{-1}\)
C. \((1.08P)^{-5}\)
D. \((1.08)^{-5}P\)
E. \((1.08)^{-5}P^5\)
22 Nov 2019, 09:32
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first to second year: 1.08P
second to third year: 1.08x1.08xP = (1.08)^2P
....... AND SO ON.
SO TO GO BACK 5 Years, exponent P will be negative.... Answer (D)
second to third year: 1.08x1.08xP = (1.08)^2P
....... AND SO ON.
SO TO GO BACK 5 Years, exponent P will be negative.... Answer (D)
22 Nov 2019, 13:14
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Bunuel
For each of the last 5 years, the population of a colony of beetles increased by 8 percent of the preceding year's population. If P represents the current population of the colony, which of the following best represents the population 5 years ago, in terms of P?
A. \((5)(1.08 P^{-1})\)
B. \((1.08)^{-5}P^{-1}\)
C. \((1.08P)^{-5}\)
D. \((1.08)^{-5}P\)
E. \((1.08)^{-5}P^5\)
A. \((5)(1.08 P^{-1})\)
B. \((1.08)^{-5}P^{-1}\)
C. \((1.08P)^{-5}\)
D. \((1.08)^{-5}P\)
E. \((1.08)^{-5}P^5\)
let x be population 5 years back ..then
x(1+8/100)^5 = P
x(1.08)^5 = P
x = P/(1.08)^5
x = P*(1.08)^-5
Ans D
