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This problem can be solved even easier I stated earlier:

Well we know that (Z + 2)(Z^2 + 4Z + 3) can be simplified=(z+1)(z+2)(z+3)

Q: is (z+1)(z+2)(z+3) divisible by 4?

This expression is divisible by 4 only in two cases:
I. z is odd (z+1 - even and z+3 also even, thus their multiplication is divisible by 4)
II. When z+2 is divisible by 4.

so let's check statements:

(1) z=8k --> z is not odd, z+2=8k+2 is not divisible by 4 --> expression is not divisible by 4. Sufficient

(2) z=3n-1 --> z is even, but not sure whether it's divisible by 4 or not. Not sufficient

Answer: A.
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yangsta8
For positive integer Z, is the expression (Z + 2)(Z^2 + 4Z + 3) divisible by 4?
1. Z is divisible by 8.
2. (Z+1)/3 is an odd integer.

This is my approach...

GIVEN:
(z+1)(z+2)(z+3) are consecutive integers...
We know that the multiple of 4 appears in this pattern: 1,2,3,(4),5,6,7,(8),9,10,11,(12),...
As you have noticed, after a multiple of 4, it will be followed by 3 non-multiple of 4...

1.
If z is a multiple of 4, then z+1,z+2,z+3 are all non-multiple of 4 based on the pattern above...
SUFFICIENT.
2.
Let z+1 = 3: (3)(4)(5) is divisible by 4
Let z+1 = 9: (9)(10)(11) is not divisible by 4
INSUFFICIENT.

Answer: A
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