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Bunuel
Garcia purchased two kinds of coffee – mild and hearty – from Harbucks Coffee Emporium. If each pound of mild coffee costs $1.40 and each pound of hearty costs $1.50, how many pounds of mild did Garcia buy?

(1) The total value of the coffee Garcia purchased was $8.95.
(2) Garcia purchased a total of 6.5 pounds of coffee.

This question is trying to trick you into assuming "integer solutions". Note that it doesn't say that coffee must be bought in 1 pound packets only. Another clue is there is statement 2. Total amount of coffee purchased is 6.5 pounds, not an integer.

Hence, if m is the amount of mild coffee purchased and h is the amount of hearty coffee purchased, m and can take any positive values.

(1) The total value of the coffee Garcia purchased was $8.95.

1.4m + 1.5h = 8.95
Two variables, 1 equation. Not sufficient.

(2) Garcia purchased a total of 6.5 pounds of coffee.
m + h = 6.5
Two variables, 1 equation. Not sufficient.

Using both statements, 2 variables and 2 distinct equations. Will be sufficient. We don't really need to solve.
Answer (C)

Note: There is a problem with the numbers as given. When we solve it actually, we see that average price of coffee is 8.95/6.5 = 1.377
But the average price must be between 1.4 and 1.5 since a mix of those two prices is bought.
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Please correct the question:

I think the (ii) statement should be -

(2) Garcia purchased a total of 6.0 pounds of coffee.



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