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Difficulty:
45%
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Question Stats:
67% (02:08) correct
33%
(02:20)
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Given two points P = (3, 0) and Q = (0, 6), find the co-ordinates of the point A, lying on the line x = - y, so that the triangle PAQ has the least possible perimeter.
(A) ( 1, -1 )
(B) ( -1, 1 )
(C) (-0.5,0.5)
(D) ( 2, -2)
(E) (0,0)
(A) ( 1, -1 )
(B) ( -1, 1 )
(C) (-0.5,0.5)
(D) ( 2, -2)
(E) (0,0)
01 Dec 2019, 02:44
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CaptainLevi
Given two points P = (3, 0) and Q = (0, 6), find the co-ordinates of the point A, lying on the line x = - y, so that the triangle PAQ has the least possible perimeter.
(A) ( 1, -1 )
(B) ( -1, 1 )
(C) (-0.5,0.5)
(D) ( 2, -2)
(E) (0,0)
(A) ( 1, -1 )
(B) ( -1, 1 )
(C) (-0.5,0.5)
(D) ( 2, -2)
(E) (0,0)
for the ∆ PAQ to have least perimeter the distance of QA has to be minimum possible at when the point A is at origin (0,0)
IMO E
02 Dec 2019, 01:44
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CaptainLevi
Given two points P = (3, 0) and Q = (0, 6), find the co-ordinates of the point A, lying on the line x = - y, so that the triangle PAQ has the least possible perimeter.
(A) ( 1, -1 )
(B) ( -1, 1 )
(C) (-0.5,0.5)
(D) ( 2, -2)
(E) (0,0)
(A) ( 1, -1 )
(B) ( -1, 1 )
(C) (-0.5,0.5)
(D) ( 2, -2)
(E) (0,0)
As line Equation is X= -Y
Line will cross through (0,0), From Quandrant 2 & 4.
with Only Point (0,0), will give Perimeter of Triangle PAQ least. Else, for other points , it will increase.
IMO-E
Please give kudos, if You find my explanation good Enough 
