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GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) =

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Bunuel
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GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 07:30
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00:00
A
B
C
D
E

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Question Stats:

89% (00:42) correct 11% (00:45) wrong based on 79 sessions
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\(\sqrt{99 }- \sqrt{44 }+ \sqrt{11 }=\)


A. \( \sqrt{11}\)

B. \(2 * \sqrt{11}\)

C. \(\sqrt{66}\)

D. 12

E. \(6 * \sqrt{11}\)




Happy New Year Australia/Northern Territory!

Dec 31 Event: GMAT Club Around The World!
(38 new questions posted every hour time zone on Dec 31!)

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B
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EgmatQuantExpert
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 07:34
Expert Reply
Given

    • √99 - √44 + √11


To Find

    • The value of the expression.

Approach and Working Out


    • √99 - √44 + √11
      o = √11 (√9 - √4 + 1)
      o = √11 (3 – 2 + 1)
      o = 2√11

Correct Answer: Option B
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 08:01
\(\sqrt{99} - \sqrt{44} + \sqrt{11}\)=

= \(\sqrt{11*9} - \sqrt{11*4} + \sqrt{11}\)

= 3\(\sqrt{11} - 2\sqrt{11} + \sqrt{11}\)

= 2\(\sqrt{11}\)

Answer B.
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 08:05
√99 = √9*√11 = 3√11
√44 = √4*√11 = 2√11

√99 - √44+ √11 = 3√11 - 2√11 + √11 = √11(3-2+1) = 2√11

Option B.
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 08:08
V11(V9-V4+1)=2V11

PUSH B
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 08:14
\(\sqrt{99}-\sqrt{44}+\sqrt{11} = \sqrt{11}(3-2+1) = 2*\sqrt{11}\)
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 09:38
The answer is B

√99−√44+√11= 3√11 - 2√11 + √11 = √11 * (3-2+1) = 2*√11
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 09:50
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Bunuel wrote:
\(\sqrt{99 }- \sqrt{44 }+ \sqrt{11 }=\)


A. \( \sqrt{11}\)

B. \(2 * \sqrt{11}\)

C. \(\sqrt{66}\)

D. 12

E. \(6 * \sqrt{11}\)



Happy New Year Australia/Northern Territory!

We can try taking out the squares first and see what happens:


\(\sqrt{99 }- \sqrt{44 }+ \sqrt{11 }=3\sqrt{11} - 2\sqrt{11} + \sqrt{11} = 2\sqrt{11}\).

Ans: B
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 10:20
IMO B
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 11:03
IMO B

√99−√44+√11
= 3√11−2√11+√11
=2√11
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 12:56
√99−√44+√11= 3√11- 2√11+√11= 4√11-2√11= 2*√11

So, It is B. :)
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   31 Dec 2020, 16:29
IMO B 2root11

taking root11 common from the equation and then solving it will give the required result.
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   01 Jan 2021, 06:54
answer is b) 2 * underroot 11

3* underroot 11 - 2* underoot 11 + underoot 11

gives 2 underroot 11

so answer is b )
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   01 Jan 2021, 07:17
Correct Answer B

99^(1/2) - 44^(1/2) + 11^(1/2)

\sqrt{99}-\sqrt{44}+\sqrt{11}
=3\sqrt{11}-2\sqrt{11}+\sqrt{11}
=2\sqrt{11}
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   02 Jan 2021, 19:03
√99 - √44 + √11
√9*11 - √4*11 + √11
3√11 - 2√11 + √11
2√11
So the answer will be B
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink] New post   03 Jan 2021, 05:56
Bunuel wrote:
\(\sqrt{99 }- \sqrt{44 }+ \sqrt{11 }=\)


A. \( \sqrt{11}\)

B. \(2 * \sqrt{11}\)

C. \(\sqrt{66}\)

D. 12

E. \(6 * \sqrt{11}\)


Happy New Year Australia/Northern Territory!

Dec 31 Event: GMAT Club Around The World!
(38 new questions posted every hour time zone on Dec 31!)




In the expression, take 9, 4 and 1 out from the exponents in the respective terms. This simplifies the expression to:

3(11)^0.5 - 2(11)^0.5 + (11)^0.5
-> 2(11)^0.5

Thus, IMO option B is correct.
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Re: GMAT Club Around The World!!! 99^(1/2) - 44^(1/2) + 11^(1/2) = [#permalink]
03 Jan 2021, 05:56
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