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A palindrome is a number that reads the same when read from either end. For example, 12321 is a palindrome. A set consists of all the 3-digit palindromes whose product of digits has 1 as the unit digit.

Let the 3 digit palindrome be xyx ; x & y are digits and where product of digits x^2y has 1 as unit digit.
(x,y) = {(1,1),(3,9),(7,9),(9,1)}
Set of 3-digit palindromes = {111,393,797,919}

Select for Minimum the minimum possible value of the tens digit of any of the numbers in the set, and select for Maximum the maximum possible value of the tens digit of any of the numbers in the set. Make only two selections, one in each column.

Minimum the minimum possible value of the tens digit of any of the numbers in the set = 1
Maximum the maximum possible value of the tens digit of any of the numbers in the set = 9


MinimumMaximum
19

 
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Bunuel
A palindrome is a number that reads the same when read from either end. For example, 12321 is a palindrome. A set consists of all the 3-digit palindromes whose product of digits has 1 as the unit digit. Select for Minimum the minimum possible value of the tens digit of any of the numbers in the set, and select for Maximum the maximum possible value of the tens digit of any of the numbers in the set. Make only two selections, one in each column.

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­A three digit palindrome means unit and hundredth digit is same and tenth digit can be same or different. So, let a be the unit and hundredth digit and b be the tenth digit.
b * (a) ^2   unit digit is 1  means neither a or b can be even (including 0).
Subsequently putting the value of a and b from 1, 3, 5, 7, and 9.
We get answers as
a = 1 and b = 1
a =9 and b = 1
a= 3 and b = 9
a = 7 and b = 9

These are the only possible vaules. and the highest and lowest values of b ( tenth digit), we get are 9 and 1 respectively.
Minimum: 1
Maximum: 9
 
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Let three digit number be 111,We can easily see that the product of the numbers is 1 with unit digit being 1 implies the number is 111 hence for minimum tens digit number is 1 and for maximum tens digit is 1

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A palindrome is a number that reads the same when read from either end. For example, 12321 is a palindrome. A set consists of all the 3-digit palindromes whose product of digits has 1 as the unit digit. Select for Minimum the minimum possible value of the tens digit of any of the numbers in the set, and select for Maximum the maximum possible value of the tens digit of any of the numbers in the set. Make only two selections, one in each column.

product of digits is
aba ; a*b*a unit digits is 1
the minimum possible value of the tens digit of any of the numbers in the set ; 909

maximum possible value of the tens digit of any of the numbers in the set ; 393
909 , 393
Minimum tens digit ; 0 at 909
Maximum tens digit ; 9   at 393 correct option
(0,9)
­
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We know 9*9 is 81

So what's biggest single digit square that has 9 in unit place 7.

So 797 will have 1 in units digit.Hence 9 is maximum.


We can't use 101 as it's unit digit will be 0.

So 111 will give product 1.

Hence 1 is minimum

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A palindrome is a number that reads the same when read from either end. For example, 12321 is a palindrome. A set consists of all the 3-digit palindromes whose product of digits has 1 as the unit digit. Select for Minimum the minimum possible value of the tens digit of any of the numbers in the set, and select for Maximum the maximum possible value of the tens digit of any of the numbers in the set. Make only two selections, one in each column.­

The possible 3 digits numbers whose product will end with 1 at units place are:

(1, 1, 1) 
(1, 3, 7)
(1, 9, 9)
(3, 3, 9)
(7, 7, 9)

It is obvious that we can't have 0 since the product will become 0. 

Now to have palindrome, it will be in format aba, so product will be a^2*b

We need to find min and max value of b

Let's try for b = 1, then a^2 must end with 1, (a = 1, a = 9) Hence possible, hence min value for b is 1
Let's try for b = 9, then 2^2 must end wit 9 (a = 3, a = 7) Hence possible, hence max value for b = 9

Hence answer is (1, 9)
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We can check the no. by multiplying the digits with the square of every digit to check if the unit digit is one.

0 is not possible because then the product of digits will be 0.

The minimum will be '1' because it will form the palindrome 111, which satisfies the condition.

The maximum will be '9' because it will form palindromes like 393, etc., which satisfies the condition.
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Smallest tens digit
­Smallest possible digit is 0,
however if 0 is there, then the unit digit of product will be 0. hence not possible. 
Next smallest digit is 1
if we take the 111, which is a palindrome, the unit digit of product will be 1. Hence smallest possible tens digit = 1.

Largest tens digit
Largest digit is 9
lets consider a 3 digit pallindrom as x9x
for unit digit to be 1, x*x should have a unit digit of 9, which is possible when x = 3
hence 393 will have their unit digit of product as 1. Hence largest possible tens digit = 9.

 
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IMO

Minimum - 1
Maximum - 9


111 = 1 (product is 1)

Now listing all the digits product as 1 at the unit;s place - 11,21,31,41,51,61,71,81,91

Notice all the numbers are prime numbers except 21,51 and 81 . So our best bet is 919 = 81 hence 8 is the maximum.
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­MinimumMaximum 013579
set={1_1,1_1,.....}=_____1

min=1
max=9
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My answer is

Minimum - 1 for example...111 and 919

Maximum - 9 for example - 393
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The 3-digit palindromes whose product of digits has 1 as the unit digit are those who hase on the left and side number of 1 and 9
but also numbers that has 7 on the left and right and 9 in between.
so the minimum (starting from the very low ones which is 0) cannot be 0, since the product would not be 1
ont the other hand 1 can be for example 919 So the Minimum on the thens is 1 ,
On the other hand, there is nonrestriction on 9, we can say 191, so the maximum number of the tens is 9
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­All 3 digit pallindrome nos whose product is 1

Min value is 1
Max value is 1
 ANS BB
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So the question refers to 3-digit palindromes. Since the first and last digits must be the same, we can write this like this

X Y X

The next bit of crucial information is that the product of the digits has 1 as the unit digit. We can write that as follows

X*Y*X = ____1

Lastly we are asked to find the minimum possible value of the tens digit of any of the numbers in the set and the maximum possible value of the tens digit of any of the numbers in the set.

First let's have a look at all the digits that are possible for X. 

0 - Not possible
1 - Possible as the multiple of the digits in 111 equals 1 and therefore a valid palindrome.
2 - 2*2 = 4, and no multiple of 4 ends in a 1, so NOT possible.
3 - 3*3 = 9, and 9*9 = 81 which ends in a 1 so 393 is a valid palindrome.
4 - 4*4 = 16 and no multiple of 16 ends in a 1 so NOT possible.
5 - 5*5 = 25 and no multiple of 25 ends in a 1 so NOT possible.
6 - 6*6 = 36 and like with 4, no multiple of 36 ends in a 1: NOT possible
7 - 7*7 = 49 and 49*9 will end in a 1, so 797 is a valid palindrome. 
8 - 8*8 = 64 and no multiple of 64 ends in a 1 so NOT possible
9 - 9*9 = 81, which when multiplied by 1 will end in 1 so 919 is a valid palindrome. 

As we can see, there are four valid palindromes and if we look at the tens value, it is either 9 or 1

Therefore
Maximum: 9
Minimum: 1
Bunuel
A palindrome is a number that reads the same when read from either end. For example, 12321 is a palindrome. A set consists of all the 3-digit palindromes whose product of digits has 1 as the unit digit. Select for Minimum the minimum possible value of the tens digit of any of the numbers in the set, and select for Maximum the maximum possible value of the tens digit of any of the numbers in the set. Make only two selections, one in each column.

­
 


This question was provided by GMAT Club
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Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 

­
­
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A palindrome is a number that reads the same when read from either end. For example, 12321 is a palindrome. A set consists of all the 3-digit palindromes whose product of digits has 1 as the unit digit. Select for Minimum the minimum possible value of the tens digit of any of the numbers in the set, and select for Maximum the maximum possible value of the tens digit of any of the numbers in the set. Make only two selections, one in each column.­

Answer ->
For minimum -

The minimum possible value of the tens digit can not be 0 as the product will be 0.

Let us take 111. It meets all the condictions and 1 is the minimum possible value of the tens digit.

For maximum-
Let us take 393. The product is 3*9*3 = 81 and it meets all the condictions. 9 is the maximum possible value of the tens digit.

Hence, 1 is the minimum possible value of the tens digit and 9 is the maximum possible value of the tens digit.

 
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A 3-digit palindrome looks like
ABA, where the first and last digits are the same, and the middle digit can be different.
We need to find such palindromes where the product of the digits has 1 as the last digit. For example, in
121, the product is 1×2×1=2, which doesn't work. We need the product to end in 1.
We check numbers and see that only certain digits work.
Checking digits:
For the first and last digit (A):A can be 1, 3, 7, or 9. These values make the product of the digits end in 1.
For the middle digit (B):If A=1 or A=9, B must be 1 because 1×1=1.
If A=3 or A=7, B must be 3 or 7 because
9×3=27 and 9×7=63, both ending in 1.
Simplified results:
The middle digit (B) can be 1, 3, or 7.
The smallest value for B is 1.
The largest value for B is 7.
So, the minimum possible tens digit is 1, and the maximum possible tens digit is 7.
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Bunuel
A palindrome is a number that reads the same when read from either end. For example, 12321 is a palindrome. A set consists of all the 3-digit palindromes whose product of digits has 1 as the unit digit. Select for Minimum the minimum possible value of the tens digit of any of the numbers in the set, and select for Maximum the maximum possible value of the tens digit of any of the numbers in the set. Make only two selections, one in each column.

­
 


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3 digit palindromes whose product of digits has 1 as unit digit

i.e 3 digit palindromes could be aba or aaa
so product of digits = a^2*b has 1 as unit digit
a cannot be 2 , 4,5,6,8 and could be 1,3,7,9 and b could be anything 9 or 1
so minimum set could be 111 so minimum tens digit becomes 1

maximum tens digit could be 393 or 797 so it could be 9


so minium is 1
maximum is 9 

 
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