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GuadalupeAntonia
Yale Moderator
Joined: 04 May 2024
Last visit: 23 Aug 2025
Posts: 59
Given Kudos: 22
Location: Mexico
Schools: Haas '27 Yale '27 Stanford '27 MIT '27 Wharton '27
GMAT Focus 1: 665 Q84 V83 DI80 
GPA: 3.5
Schools: Haas '27 Yale '27 Stanford '27 MIT '27 Wharton '27
GMAT Focus 1: 665 Q84 V83 DI80
Posts: 59
09 Jul 2024, 11:26
Kudos
Bookmarks
9 individuals
_ _ _ _ ? _ ? _ _
Senior citizen =1
Children
Young Adult
Middle Age Adult
Teenager
The first or the last seat is occupied by a senior citizen
_ _ _ _ ? _ ? _ S
There are more middle-aged adults than individuals of any other age group. There are fewer teenagers than children, young adults, or middle-aged adults. .
MA>C>=YA>T>=S
MA+C+YA+T+S=9
S=1
The first three individuals from the left are a young adult, a teenager, and another young adult
YA T YA _ ? _ ? _ S
We are missing to fill 5 seats and missing to place children and middle age adults
so the only combination possible is
2 Children
3 Middle age adult
as MA>C and MA>T MA>YA and MA>S
we already have 2 Young Adult so Middle Age must be more than 2, but less than 4 because we miss to place children and members of the same group can't seat together and T<C and T<YA we need at most 2 children in order to be less than 3 Middle adults and to fulfill the 5 missing seats. so
MA =3
YA =2
T =1
C= 2
S= 1
MA+C+YA+T+S=9
3+2+2+1+1=9
YA T YA MA C MA C MA S
5th place Children
7th place Children
_ _ _ _ ? _ ? _ _
Senior citizen =1
Children
Young Adult
Middle Age Adult
Teenager
The first or the last seat is occupied by a senior citizen
_ _ _ _ ? _ ? _ S
There are more middle-aged adults than individuals of any other age group. There are fewer teenagers than children, young adults, or middle-aged adults. .
MA>C>=YA>T>=S
MA+C+YA+T+S=9
S=1
The first three individuals from the left are a young adult, a teenager, and another young adult
YA T YA _ ? _ ? _ S
We are missing to fill 5 seats and missing to place children and middle age adults
so the only combination possible is
2 Children
3 Middle age adult
as MA>C and MA>T MA>YA and MA>S
we already have 2 Young Adult so Middle Age must be more than 2, but less than 4 because we miss to place children and members of the same group can't seat together and T<C and T<YA we need at most 2 children in order to be less than 3 Middle adults and to fulfill the 5 missing seats. so
MA =3
YA =2
T =1
C= 2
S= 1
MA+C+YA+T+S=9
3+2+2+1+1=9
YA T YA MA C MA C MA S
5th place Children
7th place Children
09 Jul 2024, 11:35
Kudos
Bookmarks
In the table, select the age group of the Fifth individual from the left and the age group of the Seventh individual from the left.
Fifth individual- Middle-aged adults and the Seventh individual- Children.
Based on the scenarios provided.
Fifth individual- Middle-aged adults and the Seventh individual- Children.
Based on the scenarios provided.
09 Jul 2024, 11:35
Kudos
Bookmarks
Bunuel
First let's define: children (C), teenagers (T), young-adults (YA), middle-aged adults (A) and senior citizens (S)
Extracting the most from the information above, we know each category has a minimum 1 person, with S = 1
We are left with 8 seats.
Next category with the smallest number is T, followed by C and YA (we don't know their relationship) and A (which is largest number). So 1 <= T < C/YA < A and T+C+YA+A = 8. From here we can easily deduce that, if T is 2 or greater, the sum exceeds 8 (2 + 3 + 3 + 4 = 12). So T is 1 and its position in the line-up is already determined, while C + YA + A = 7
We are left with 2 <= C / YA < A - again, if C / YA is greater than 2, we exceed the sum above. So C and YA are each 2 and A is 3.
For the arrangement, we are already given: YA-T-YA-_-_-_-_-_-S
So we have 5 slots to fill with 3A and 2C - the only way in which they do not sit next to each other is YA-T-YA-A-C-A-C-A-S
Therefore, counting from the left, 5th individual is Child and 7th individual is also Child
