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09 Jul 2024, 08:23
Kudos
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The arrangement from the left should be -
Young adult Teenager young adult Middle aged adult children middle aged adult children middle aged adult senior citizen.
Hence the answer is "children " for both fifth and seventh individual.
Young adult Teenager young adult Middle aged adult children middle aged adult children middle aged adult senior citizen.
Hence the answer is "children " for both fifth and seventh individual.
09 Jul 2024, 08:27
Kudos
Bookmarks
Let's imagine a row and plug in all we know for a moment:
Left
1 - young adult
2 - teenager
3 - young adult
4
5
6
7
8
9
Right
The first or the last seat is occupied by the senior citizen. The first place (1) is already occupied by young adult, so the senior citizen (there is only one such citizen in the group) gets the last place (9).
We know that there are more middle-aged citizens than young-adults, so there at least 3 middle-aged citizens and there are no more than 3 such citizens, because according to the rule that no two individuals from the same age group are sititng together, we can give middle-ages citizens only 3 places: 4, 6, 8
There are more children than teenagers and less than middle-ages citizens, so there are 2 children, that receive places 5 and 7
Final version looks like this:
Left
1 - young adult
2 - teenager
3 - young adult
4 - middle-aged
5 - child
6 - middle-aged
7 - child
8 - middle-aged
9 - senior
Right
Answer: Children is the age group of the Fifth individual from the left and Children is the age group of the Seventh individual from the left.
Left
1 - young adult
2 - teenager
3 - young adult
4
5
6
7
8
9
Right
The first or the last seat is occupied by the senior citizen. The first place (1) is already occupied by young adult, so the senior citizen (there is only one such citizen in the group) gets the last place (9).
We know that there are more middle-aged citizens than young-adults, so there at least 3 middle-aged citizens and there are no more than 3 such citizens, because according to the rule that no two individuals from the same age group are sititng together, we can give middle-ages citizens only 3 places: 4, 6, 8
There are more children than teenagers and less than middle-ages citizens, so there are 2 children, that receive places 5 and 7
Final version looks like this:
Left
1 - young adult
2 - teenager
3 - young adult
4 - middle-aged
5 - child
6 - middle-aged
7 - child
8 - middle-aged
9 - senior
Right
Answer: Children is the age group of the Fifth individual from the left and Children is the age group of the Seventh individual from the left.
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Goizueta / Scheller Moderator
Joined: 03 Jun 2024
Last visit: 29 May 2025
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Location: India
Schools: Ross '27 (S) Haas '27 (S) Scheller '27 (A) Goizueta '27 (I) McCombs '27 Jones '27 (II) Kenan-Flagler '27 (I)
GMAT Focus 1: 675 Q90 V81 DI79 
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Schools: Ross '27 (S) Haas '27 (S) Scheller '27 (A) Goizueta '27 (I) McCombs '27 Jones '27 (II) Kenan-Flagler '27 (I)
GMAT Focus 1: 675 Q90 V81 DI79
Posts: 85
09 Jul 2024, 08:28
Kudos
Bookmarks
Nine individuals are sitting on the dais, from left to right, to receive an award at a local club. The awardees include at least one from each of five age groups: children, teenagers, young adults, middle-aged adults, and senior citizens. The first or the last seat is occupied by a senior citizen, who is the only individual in that age group. No two individuals from the same age group are sitting next to each other. For example, no young adult is sitting next to another young adult. There are more middle-aged adults than individuals of any other age group. There are fewer teenagers than children, young adults, or middle-aged adults. The first three individuals from the left are a young adult, a teenager, and another young adult.
In the table, select the age group of the Fifth individual from the left and the age group of the Seventh individual from the left. Make only two selections, one in each column.
Let
T = Teenagers
C = Children
YA = Young Adult
MA = Middle-aged Adult
S = Senior
From the above inforation, we can make this outline
YA - T - YA - ? - ? - ? - ? - ? - S
Now since the count of MA is max, they must be more than 2 since there are 2 YA already
Keeping that in mind and that no two individuals from the same age group are sitting next to each other,
We can conclude that this should be the outline
YA - T - YA - MA - ? - MA - ? - MA - S
Now we are asked about 5th and 7th, the remaining question marks
The possibilities are {C, C}, {C, YA} and {YA, C}
We can cancel out the last two options since T < number of C (if they were true, count of T = count of C which goes against the question premise)
Hence the only possible way is {C, C} -> Answer
So the outline must be
YA - T - YA - MA - C - MA - C - MA - S
In the table, select the age group of the Fifth individual from the left and the age group of the Seventh individual from the left. Make only two selections, one in each column.
Let
T = Teenagers
C = Children
YA = Young Adult
MA = Middle-aged Adult
S = Senior
From the above inforation, we can make this outline
YA - T - YA - ? - ? - ? - ? - ? - S
Now since the count of MA is max, they must be more than 2 since there are 2 YA already
Keeping that in mind and that no two individuals from the same age group are sitting next to each other,
We can conclude that this should be the outline
YA - T - YA - MA - ? - MA - ? - MA - S
Now we are asked about 5th and 7th, the remaining question marks
The possibilities are {C, C}, {C, YA} and {YA, C}
We can cancel out the last two options since T < number of C (if they were true, count of T = count of C which goes against the question premise)
Hence the only possible way is {C, C} -> Answer
So the outline must be
YA - T - YA - MA - C - MA - C - MA - S
