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­All the routes run towards city center, so all 9 routes she has to make will lead towards it.
For Laurel Lane, 4 of the 5 routes run towards it, so at least 4 times, and then 2 others, since it cannot repeat
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Since each day distance is 10 miles, need to pick 1 or 2 route between route 1,2 and 3 and 1 route between route 4 and 5.

Picking any route in first 3, ends up in city centre so 2 times towards city center + 1 time between route 4/5. So 3 times towards city center each time. i.e. 9 times during 3 day period.

Towards Laurel lane route 1 and 2 don't have it. So once for route 4/5 and once or twice for route 3 i.e total 2 or 3 times. Since route cant be avoid for more than 2 days + 4 times the 3 day if route 3 is repeated.

Answer:
City Centre: 9
Laurel Lane: 7
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Bunuel
­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.


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­For city centre there is always a route in city centre will be there. So it will be 3*3 = 9 

For Laurel - we can do multiple ways but in all we will get 7 let us do a few :

Day 1 :Route 1,Route 2, Route 4 = 2
Day 2 :Route 3,Route 2, Route 5 = 3
Day 1 :Route 1,Route 3, Route 4 = 2

Total = 7

​​​​​​​In other ways also everytime 7 will come
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­As total distance travelled is 10 miles, each day she has to choose two routes among (1, 2, 3) and one route between (4, 5).

She chooses the first day (1, 2, 4). The second day she has to choose route 3 and 5 because she never avoids a route two days in a row. So she chooses, for example, (1, 3, 5).

The third day she can not choose 1 again because she does not run any of the routes more than two days in a row. Also, she has to choose route 2 and 4 because she never avoids a route two days in a row. So he has to choose (2, 3, 4) obligatory.

Reasoning in the same way:
- the 4th day he has to choose (1, 2, 5) obligatory.
- the 5th day he has to choose (1, 3, 4) obligatory.
- the 6th day he has to choose (2, 3, 5) obligatory.
- the 7th day he has to choose (1, 2, 4) obligatory which is equal to the selection she made the 1st day.

So, over the span of any 3-day period, she runs twice in routes 1, 2 and 3 and twice in route 4 and once in route 5 or twice in route 5 and once in route 4.

All the routes run towards the City Centre, so we have 9 times.

As 4 and 5 runs towards Laurel Lane there is no diffence between choosing twice the route 4 and once the route 5 or twice the route 5 and once the route 4.
Route 1 does not run towards Laurel Lane, so we have 7 times.
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Bunuel
­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.


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­Given details,
1) 3 routes every day
2) 10 miles/day
3) No route is repeated for more than 2 days in a row.
4) No route is avoided for more than 1 day in a row.

Route detais, 
1) Each route is going towards city center
2) 4 out of 5 routes are having Laurel Lane in the path.

So, to run for 3 days period runner will for 9 times and every time city center will be there.

1st column: 9

Considering the possible route selection(3 routes/day and 10 miles/day) for 3 days: (R1, R2, R4), (R1, R3, R5), (R2, R3, R4)
Now in any case R1 will be there for 2 times which is not having Laurel Lane in the path.
So, 7 routes are there having Laurel Lane in the path over the span of 3 days.

2nd column: 7
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Given the runner needs to cover 10 miles per day, she will always combine two 3-mile routes and one 4-mile route.

As there are three days and restrictions on both repeating and not repeating the routes, she will take a different combination of two 3-mile routes every day, which means she will run each of them twice.
From this we can safely say that she will run to City Centre 3*2 = 6 times and to Laurel Lane 2*2 = 4 times.

As for the 4-mile routes, she will either run 4-5-4 or 5-4-5. But in both cases, she will run to City Centre and to Laurel Lane 3 times per three days, regardless of this combination.

In total, her CC routes will be \(6+3 = 9\), and her LL routes are \(4+3=7.\)­
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­


only Route 1 does not Contain Laurel Lane, So City Centre = 9, Laurel Lane = 7
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­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.

Based on all the INFO

Day 1.      R1-R2-R4 
Day 2.      R1-R3-R4
Day 3.      R2-R3-R5

Towards city center
Day 1: 3
Day 2: 3
Day 3: 3
Total : 9

Towards Laurel Lane
Day 1: 2
Day 2: 2
Day 3: 3
Total: 7
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The runner has to cover 10 miles. So 2 3-mile + 1 4-mile routes every day
Even on changing selections at any frequency, the runner has to run towards city center 3 times each day for each of the routes
And the runner has to run towards Laurel Lane once at any cost for 3-mile and once at any cost for 4-mile. Hence 2 times each day

Thus for 3 days, CC: 3*3 = 9
LL: 2*3 = 6
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Note: I may have chosen the wrong answer but the explanation below is for the correct answer (3 and 7). 

Solution: Notice that no matter what routes she takes in a day, she will have to run toward City Centre 3 times a day.

For Laurel Lane, notice that only Route 1 does not have Laurel Lane. Let's try to create a running plan for three days that minimizes the number of times that she has to run toward Laurel Lane.

Day 1: Route ("R") 1, R2, R4 (running toward Laurel Lane twice)
Day 2: R3, R5 (Note: R3 and R5 did not appear Day 1 so she necessarily has to take these routes today), R1 (running toward Laurel Lane twice)
Day 3: R2, R4, R3 (Note: No mor R1 because she cannot repeat that three times in a row) (running toward Laurel Lane three times)

In this Laurel-Lane-minimal schedule, she runs toward Laurel Lane only ­2 + 2 + 3 = 7 times

The correct answer is thus:City CentreLaurel Lane X36X789
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­part one - City centre = 9
All 5 routes go towards city centre at the end, so every day she runs towards city centre three times. In 3 days, that makes 3 x 3 = 9 times

part two - Laurel Park = 8
She runs 10 miles every day, this means she runs two of the 3 mile courses and one 4 mile course on any given day. This is the only possible combination given the choices, it makes our work easier. Two out of three of the 3-mile courses go towards laurel park, and both of the 4-mile courses go towards laurel park. 

list possible route choices for three days within the constraints, here is an example. listing any three other possibilities gives the same answer because of the nature of the constaints. 
example - 
1, 2, 4
2, 3, 4
1, 3, 5
Times ran towards laurel park = 3+3+2 = 8 times in total 

 
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Bunuel
­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.


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­So one of the possibility is:

D1                       D2                      D3
R1,R2,R4           R2,R3,R5           R3,R1,R4

So for all It travels towards city center. Hence 9. 

Laurel lane : Hence 7;

IMO 9,7 
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From the given information, for a 3 day period the route can be - 1,2,4 & 1,3,4 & 2,3,5
So from this we can look for number times the runner goes towards City center and Laurel lane.
Hence, we get City center 9 times and Laurel lane 6 times.
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Quote:
­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.
Let's plan out the three days as per the conditions:-

Day 1: R1, R2, R4
Day 2: R1, R3, R4
Day 3: R2, R3, R5

This is one instance of how no repeating routes are allowed and total 10 miles is distance.

Calculate the number of City Hall and Laurel Lane visits on these routes in total, we get:-

City Centre: 9
Laurel Lane: 7
­
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Bunuel
­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.


­
 


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­Each day, the runner's total distance travelled is 10 miles and runs 3 predetermined routes every day. This means, out of the 3 runs, 2 runs are of 3 miles i.e., from Route 1, 2, or 3 (2 routes out of 3 routes will be selected daily). And one run will be of 4 miles i.e., route 4 or route 5.
2 * (3 miles) + (4 miles)  = 10 miles 

Now, she does not run any of the routes more than two days in a row and never avoids a route two days in a row. So, in selecting 2 out of 3 routes from Route 1, 2, and 3, we should keep in mind the limitation. This can only be done in a rotatory pattern of 3 days similar to that of below:
Day 1: Route 1 and 2
Day 2: Route 2 and 3
Day 3: Route 1 and 3

Basically in all 3 days pattern similar to this, every route out of Route 1, 2, and 3, will be run by the runner exactly two times.

Now, talking about the 4 miles route i.e., Route 4 and 5. Out of the two, exactly one will be selected daily. By keeping in mind the rule "she does not run any of the routes more than two days in a row and never avoids a route two days in a row", this can be done in two ways as below:
1. Alternately choosing between Route 4 and Route 5 each day.
2. Consecutive 2 days on Route 4 and then consecutive 2 days on Route 5 (and vice versa)

Now, answering the questions: the number of times the runner will run towards the city centre over the span of any 3-day period:
As routes have city center, so running every route the runner will approach toward the city centre. So, 3 (routes) * 3 (days) = 9 times

The number of times the runner will run towards Laurel Lane over the span of any 3-day period: Only Route 2 and 3 have the (out of the 3 mile route) have the Laurel Lane. And Each route is run twice over the 3 days period. So, 4 times through 3 miles route in 3 days period.
 and on the 4 mile route (i.e., route 4 or 5) daily run, every day the runner will run towards Laurel Lane over the span of any 3-day period

So, Total = 4 + 3 = 7
 ­
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Route Analysis
Route 1: 3 miles
Route 2: 3 miles
Route 3: 3 miles
Route 4: 4 miles
Route 5: 4 miles


Constraints and Calculations

The only combinations of routes that total 10 miles are
3+3+4 miles (Routes 1, 2, or 3 combined with Route 4 or 5)

Frequency Analysis
City Centre:
Every route starts and ends at the City Centre.
Total trips towards City Centre per day: 3 times per route (start and end for each of the 3 routes).

Laurel Lane:
Routes passing through Laurel Lane: Routes 2, 3, 4, 5.
In 3 days, we have the following pattern possibilities to fulfill both conditions:
Day 1: Route 1, Route 2, Route 4
Day 2: Route 3, Route 1, Route 5
Day 3: Route 2, Route 3, Route 4
Each day, Routes involving Laurel Lane (2, 3, 4, 5) run through Laurel Lane at least once.

Selections: City Centre 3 routes/day×3 days×2 trips/route=18 trips

Laurel Lane: Based on the route pattern:
At least one route involving Laurel Lane each day, given the constraints, results in multiple trips
towards Laurel Lane.

For the options provided:

City Centre: 9
Laurel Lane: 6

Given the specific constraints and available routes:

The runner will run towards City Centre 9 times in a 3-day period (since 3 routes per day, returning each time).
The runner will run towards Laurel Lane 6 times in a 3-day period based on the pattern of routes run each day.
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­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)


A cross-country runner trains by running three predetermined routes every day. Each day, her total distance traveled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, choose the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.



Solution: Given that
  • The runner train runs three predetermined routes every day.
  • The total distance traveled is 10 miles each day.
  • No route was taken more than two days in a row.
  • No route was avoided two days in a row.

For 3 days, the possible combinations of routes amounting to 10 miles/day can be
Day 1: Route 1, Route 2, Route 4
Day 2: Route 2, Route 3, Route 5
Day 3: Route 1, Route 3, Route 4

For routes 1-5, the City Centre is crossed once each route, so a total of 3 times each day or 9 times
For routes 2-5, Lauren Lane is crossed once each route, so a total of 2 times on Day 1 + 3 times on Day 2 + 2 times on Day 3 = 7 times



 ­
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