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Firstly, he 10 miles are broken down into, 3+3+4 miles. Hence, The total number she has run towards City Centre is 9. Bcoz, each run ends with her running towards city centre.
As for the Laurel lane, the answer is 7.
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Bunuel
­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.


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­Answer is 9 for city centre and 7 for lauren lane
we have to take 3 routes daily and cover 10 miles in total
cond- no routes more than two days in a row and never miss a route two days in a row.

hence Day 1 Route is Route 1, then 2 then 4. so 3 city centre and 2 lauran lane
         Day 2 Route is Route 2, then 3 then 5. so 3 city centre and 3 lauran lane
         Day 3 Route is Route 1, then 3 then 4. so 3 city centre and 2 lauran lane
hence total = 9 for city centre and 7 for lauren lane
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Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period.

on any given day it will run 3 times towards city center so , 9 times total

For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period.


124 , 125, 234,235 ; atleast 7 times it will run towards Laurel lane of any 3 day period

9;7 is correct
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City Center - 9 and laurel lane -8

We need to make sure total 10 miles is run every day so we need to make 3+3+4 miles arrangement everyday.

Also city center is part of every route the athlete takes 3+3+3 (Every day 3 times and for 3 days so total 9 times)

Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

Now for Laurel Lane

Consider,
R1-R2-R4 ( 3 times) - Day 1
R2-R3-R5 ( 3 times) -Day 2
R1-R3-R4 ( 2 times) - Day 3
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­Answer:
City centre: 9
Explanation: there is a city centre in every route, so 3 times 3 days = 9
Laurel Line: 7
Explanation: there is one route that has no Laurel Line, you can't miss a route two days in a row, adn you need every day to run Two routes from Route 1 to 5 because Route 4 and 5 acan't be run on the same day or it would be mroe than 10 miles.
So in 3 days, she will run each route from 1 to 3, two times, so she will have from the 9 routes, twice a route with no Lauren Line, so 9-2 = 7
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Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

A possible combination for 3 day period
Day 1: Route 1 - Route 2 - Route 4
Day 2: Route 1 - Route 3 - Route 5
Day 3: Route 2 - Route 3 - Route 4

Number of times the runner will run towards the City Centre  = (1 + 1 + 1) + (1 + 1 + 1) + (1 + 1 + 1 ) = 9
Number of times the runner will run towards the Laurel Lane  = (0 + 1 + 1) + (0 + 1 + 1)  + (1 + 1 + 1 ) = 7

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.
­
Number of times the runner will run towards the City Centre  = 9
Number of times the runner will run towards the Laurel Lane  = 7
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­The way to run 10km is to follow the following route schedule in a repeating cycle every 3 days: 
day 1: R4+R1+R2
day 2: R5+R2+R3
day 3: R4+R1+R3
This gives 10k everyday and follows all the rules. Note that R1,R2,R3 can be replaced as long as we have 2 instances of each within a 3 day cycle. 
number of times the runner will run towards the city centre over the span of any 3-day period
City centre: 9 - since every route ends here. 
Laurel Lane: 7 - we have only 1 route named as R1 which doesn't have this destination on the way. So, we'll have 7 instances in 3 day period. 
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­R1-3 Mile 
R2-3 Mile
R3-3 Mile
R4-4 Mile
R5-4 Mile

Since we need to cover 10 miles so,  R4 and R5 will be taken on alternative days along with 2 differnets routes out of available 3 routes like (R1R2, R1R3, R2R3) in any order. This ensures that no two routes are taken in consecutive days and no routes are avoided two days in a row.

All 5 routes requires the runner to run towards the city centre. 
Hence in a three day period, runner will be running towards city center 9 times (3 times each day).

Apart from R1, all remaining 4 routes requires the runner to run towards the Laurel Lane.
Hence in a three day period, runner will be running towards Laurel Lane 7 times (That is total 9 times - 2 times in which she takes R1)
 
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Bunuel
­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period. For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period. Make only two selections, one in each column.


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­on every day she will run towards city center as all routes ends at city center. hence 9.
In case of laurel lane she has to avoid laurel lane on one day as out of 5 4 routes including running towards laurel lane. hence 8.

IMO 9 and 8.
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­There must be 2 3-mile routes and 1 4 mile route everyday. 

With the conditions given, City centre must be passed through in all 3 routes in all 3 days. Therefore, 9 times.

In all combinations, Route 1 will be used 2 times over the course of 3 days. Route 1 does not have Laurel Lane.

Therefore, the runner must pass through the lane 7 times.

Therefore, Option 1 is 9 and Option 2 is 7
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for 10 miles, Routes should be [3,3,4]={R1/R2/R3, R1/R2/R3, R4/R5]

All routes go through City Centre;
All except R1 goes through Laurel.

As per conditions:

Probable Routes for 3 day period:

[R1 R2 R4/R5] -> [R2 R3 R4/R5] -> [R1 R3 R4/R5]

Hence City Centre=9

Laurel= 9-2 (routes of A1)=7
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Possible Route Combinations for 10 Miles:
3 miles + 3 miles + 4 miles
so.
Day 1: Route 1 (3 miles), Route 2 (3 miles), Route 4 (4 miles) = 10 miles
Day 2: Route 3 (3 miles), Route 2 (3 miles), Route 5 (4 miles) = 10 miles
Day 3: Route 1 (3 miles), Route 3 (3 miles), Route 5 (4 miles) = 10 miles

City center visits: Every route has city center ending. So this means 3 routes per day means 3 city center. and three days mean 3x3=9. 9 times the runner gets to the city center.
Laurel Lane: Route 2 to 5 passes through Laurel Lane.
And we need exactly 10 miles per day.
So, we need to find combo for 3 days.
Day 1: Route 2, Route 4 (2 visits)
Day 2: Route 2, Route 3, Route 5 (3 visits)
Day 3: Route 3, Route 5 (2 visits)
Total: 2 + 3 + 2 = 7 visits to Laurel Lane
Thus correct answer is that city center 9 visits, Laurel Lane 7 visits.
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­City Centre = 9 times
Laurel Lane = 7 times


Given:
1. 5 routes are given ( Route 1 .... Route 5)
2. Runner choses 3 routes everyday
3. Every day runs for 10 miles
4. She does not run any of the routes more than two days in a row
5. She never avoids a route two days in a row

Route 1 - 3 miles
Route 2 - 3 miles
Route 3 - 3 miles
Route 4 - 4 miles
Route 5 - 4 miles

In order to complete 10 miles, she must chose 3 Routes with 3, 3 and 4 miles.

Day 1: R1, R2, R4
Day 2: R1, R3, R5
Day 3: R2, R3, R4

Route 4 and 5 are alternated and Routes 1,2 and 3 are chosen twice in 2 days

Question: over the span of any 3-day period
1. Number of times she runs towards City Centre
2. Number of times she runs towards Laurel Lane

by towards I am assuming that number of times she encounters

City Centre is part of all the routes.
=> she takes each route thrice everyday, and hence she runs towards it 3 times a day everyday = 3*3 = 9 times

Laurel Lane is only part of 4 out of 5 routes ( except Route 1)
=> she takes R1 on 2 out of 3 days, and every other route has this lane = 3*1 + 2*2 = 3 + 4 = 7 times
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Step 1: Understanding the Routes and their Distances
First, we list the routes and their distances:

Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

Step 2: Determine Possible Route Combinations for 10 Miles
The runner must run routes that add up to 10 miles each day. We need to check which combinations are possible:

3 + 3 + 4 = 10

4 + 3 + 3 = 10

Step 3: Determine Frequency of Running towards the City Centre
Each route starts and ends at the City Centre. Therefore, each route involves running towards the City Centre twice: once at the start and once at the end. Let's calculate the total number of runs towards the City Centre over a 3-day period.

Each day, the runner runs three routes:

Each route involves two runs towards the City Centre (start and end).
Therefore, for three routes in one day:
3 routes×2 runs towards City Centre per route=6 runs towards City Centre per day

Over a 3-day period:
6 runs per day×3 days=18 runs towards City Centre in 3 days
However, since she always returns to the City Centre, we need to count unique routes. Given three unique routes per day over three days (and she does not avoid any route more than two days in a row):

She would run towards the City Centre every time.
Therefore, the total number of times she heads towards the City Centre over 3 days is: 3×3×2=18

Step 4: Determine Frequency of Running towards Laurel Lane
Now, let's count the number of times the runner will run towards Laurel Lane. The routes that involve running towards Laurel Lane are:

Route 2 (once)
Route 3 (once)
Route 4 (once)
Route 5 (once)
Over a 3-day period, she runs three routes per day, never avoids a route for more than two days, and doesn't repeat the same route more than two days in a row. Therefore, the maximum combinations for 3 days:

Since she runs each route not more than twice and covers all routes, the combination must follow the rule of 10 miles.
Routes to Laurel Lane:
If she runs Route 2 or Route 3 or Route 4, and Route 5:

Assuming a combination of 3+3+4 (ensuring all), she runs towards Laurel Lane:

For 3 days, includes all combinations 3+3+4 and repeat next day 4+3+3, ensuring each route twice.

Hence 3 days all inclusive,

Therefore, the total number of times she runs towards Laurel Lane in any 3-day period:
[ ( 3+3+4 ) or vice versa ensuring 6 times.]

For City Centre:18

For Laurel Lane:6

Hence, the correct selections are:
City Centre: 9
Laurel Lane: 6
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Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

A cross-country runner trains by running three predetermined routes every day. Each day, her total distance travelled is 10 miles. She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

Possible routes for cosequent days:
1-2-4
1-3-4
2-3-5
1-2-5
1-3-5

Q. For the City Centre, select the number of times the runner will run towards the city centre over the span of any 3-day period.
3 times/day x 3 days=9 times

Q.For Laurel Lane, select the number of times the runner will run towards Laurel Lane over the span of any 3-day period.
Except for route 1, all routes include Laurel Lane. Other routes have been boldened.
7 times in any 3 days­
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For City Centre
Each option has to traverse once over a period of 3 days. 3+3+3 = 9 (Option E)­
For Laurel Lane
4 miles have 2 choices, out of which 1 has to be selected each day for 3 days. 3x1=3
3 miles have 2 options, out of which 2 have to be selected each day for 3 days. 1+2+1 = 4
So, total 3+4 = 7 (Option C)
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A cross-country runner trains by running three predetermined routes every day.
Each day, her total distance travelled is 10 miles.
She does not run any of the routes more than two days in a row and never avoids a route two days in a row.

Based on the above info, we will have to pick 3 routes in such a way that her total distance travelled is 10 miles.
Let's call Route 1 as R1, Route 2 as R2 and .... Route 5 as R5. 
Let's look at how to lay down the routes for each day keeping the constraints in mind. 

Day1      R1   R2   R4    (sum is 10 miles)

Day2      R2   R3   R5    (sum is 10 miles, not avoiding any route)

Day3      R1   R3   R4    (sum is 10 miles, not avoiding any route and not running a route more than two days)

This is good as we meet all the constraints.

From the below info, let's calculate the number of times the runner will run towards the City Centre over the span of above 3-day period. 
­Route 1: City Centre – Market Square – Songbird Park – City Centre (3 miles)
Route 2: City Centre – Laurel Lane – Market Square – City Centre (3 miles)
Route 3: City Centre – City Hall – Laurel Lane – City Centre (3 miles)
Route 4: City Centre – City Hall – Market Square – Laurel Lane – City Centre (4 miles)
Route 5: City Centre – Songbird Park – Market Square – Laurel Lane – City Centre (4 miles)

Counting the number of times the runner will run towards the City Centre over the span of above 3-day period, we get
Day1  3
Day2  3
Day3  3

Now, let's count the number of times the runner will run towards the Laurel Lane over the span of above 3-day period

Day1  2
Day2  3
Day3  2

Therefore, the answer choices for City Centre and Laurel Lane are 9 and 7 respectively. 
 ­
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